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2 years ago

HOLA, NECESITO AYUDA!

Physics

1 answer:

givi [52]2 years ago

6 0

The electrostatic force between the two ions is $2.9\cdot 10^{-10} N$

Explanation:

The electrostatic force between two charged particle is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, the ion of sodium has a charge of

$q_1 = +e = +1.6\cdot 10^{-19} C$

while the ion of chlorine has a charge of

$q_2 = -e = -1.6\cdot 10^{-19}C$

And the distance between the two ions is

$r=282 pm = 282\cdot 10^{-12} m$

Substituting, we find the electrostatic force between the two ions:

$F=(8.99\cdot 10^9) \frac{(1.6\cdot 10^{-19})(-1.6\cdot 10^{-19})}{(282\cdot 10^{-12})^2}=-2.9\cdot 10^{-10} N$

where the negative sign simply means that the force is attractive, since the two ions have opposite charge.

Learn more about electrostatic force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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For a moon orbiting its planet, rp is the shortest distance between the moon and its planet andra is the longest distance betwee

Natasha2012 [34]

Answer: D. 0.57

Explanation:

The formula to calculate the eccentricity $e$ of an ellipse is (assuming the moon's orbit in the shape of an ellipse):

$e=\frac{r_{a}-r_{p}}{r_{a}+r_{p}}$

Where:

$r_{a}$ is the apoapsis (the longest distance between the moon and its planet)

$r_{p}=0.27 r_{a}$ is the periapsis (the shortest distance between the moon and its planet)

Then:

$e=\frac{r_{a}-0.27 r_{a}}{r_{a}+0.27 r_{a}}$

$e=\frac{0.73 r_{a}}{1.27 r_{a}}$

$e=0.57$ This is the moon's orbital eccentricity

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3 years ago

Imagine that you are going to visit your friend. Before you get there, you decide to stop at the variety store. If you walk 200

SashulF [63]

Answer:

400m

Explanation:

Brainliest? :))

Let your initial displacement from your home to the store be

1 and your displacement from the store to your friend’s house

be Dd

Given: Dd

1 = 200 m [N]; Dd

2 = 600 m [S]

Required: Dd

Analysis: Dd

T 5 Dd

1 1 Dd

Solution: Figure 6 shows the given vectors, with the tip of Dd

joined to the tail of Dd

2. The resultant vector Dd

T is drawn in red,

from the tail of Dd

1 to the tip of Dd

2. The direction of Dd

T is [S].

T measures 4 cm in length in Figure 6, so using the scale of

1 cm : 100 m, the actual magnitude of Dd

T is 400 m.

Statement: Relative to your starting point at your home, your

total displacement is 400 m [S].

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1 year ago

A merry go round (mass of 200kg and radius 5m) is rotating so that the outside edge is moving 10m/s. A giant bug of 6kd at a dis

romanna [79]

Answer:

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Explanation:

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where $\omega$ is the angular velocity and $r$ is the radius.

$\omega=\dfrac{v}{r}$

The edge has a linear velocity of 10 m/s and the radius at the edge is 5 m.

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3 years ago

Sarah is looking for a way to move her boat across the water without touching it directly. She included paperclips in the boat d

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Answer:

When there is no detergent in the water, you'll achieve a floating paper clip!

Explanation:

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2 years ago

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A supersonic jet is at an altitude of 14 kilometers flying at 1,500 kilometers per hour toward the east. At this velocity, how f

Kaylis [27]

Answer:

The jet will fly 2400 km.

Explanation:

Given the velocity of the jet flying toward the east is 1,500 kmph toward the east.

We need to find the distance covered in 1.6 hours.

In our problem we are given speed and time, we can easily determine the distance using the following formula.

$Distance=Speed\times Time$

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So, the supersonic jet will travel 2400 km in 1.6 hours toward the east from its starting point.

3 0

3 years ago