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Brums [2.3K]
2 years ago
12

Insect A moves 5.0 m/min and insect B moves

Physics
1 answer:
mezya [45]2 years ago
6 0

Answer:

insect B by 12m

Explanation:

30min = 1800s (times by 60)

5m/min x 30min = 150m

9cm/s x 1800s = 16,200cm = 162m

162m - 150m = 12m

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A skier (m=59.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. If h = 3
marissa [1.9K]

Answer:

35.20 m

Explanation:

By the law of conservation of energy we have,

mg(H-h)=\frac{1}{2}mv^2

g(H-h)=\frac{1}{2}v^2

\Rightarrow H=\frac{v^2}{2g}+h

where m= mass of the skier, h= 3.00 m

D= horizontal distance=13.9 m

H= maximum height attained

Also, the horizontal distance covered by the skier is

D=vt

=v\frac{2g}{h}

\Rightarrow v^2=\frac{gD^2}{2h}

thus, height H in terms of D  is given by

H=\frac{D^2}{2h}+h

H=\frac{13.9^2}{2\times3}+3

H=35.20 m

4 0
3 years ago
Under specific circumstances, waves will bend around obstacles. This type of bending is called
BartSMP [9]
That type of bending is called "diffraction" of waves.
6 0
3 years ago
Put the following events in the order they occurred to lead to the formation of the solar system:
AfilCa [17]

Answer:

Third → First → Second → Fourth

Explanation:

Initially helium and Hydrogen in abundance started to form atoms

Following the atoms formation by hydrogen and helium bombardment of new matter into the Earth took place.

The bombardment of matter resulted in separation of Earth into respective layers based on the weight of the matter.

A primitive ocean was created as a result of off gassing of the volcanoes.

8 0
3 years ago
You push on a cart (18.0kg) at a 30 degree below horizontal angle. The coefficient of kinetic friction between the chair and the
podryga [215]

Given that force is applied at an angle of 30 degree below the horizontal

So let say force applied if F

now its two components are given as

F_x = Fcos30


F_y = Fsin30


Now the normal force on the block is given as

N = Fsin30 + mg

N = 0.5F + (18\times 9.8)

N = 0.5F + 176.4

now the friction force on the cart is given as

F_f = \mu N

F_f = 0.625(0.5F + 176.4)

F_f = 110.25 + 0.3125F

now if cart moves with constant speed then net force on cart must be zero

so now we have

F_f + F_x = 0

Fcos30 - (110.25 + 0.3125F) = 0

0.866F - 0.3125F = 110.25

F = 199.2 N

so the force must be 199.2 N

8 0
3 years ago
A floating boat has a weight of 100 N. What is the buoyant force on the boat?
lara31 [8.8K]
If the boat is floating, then it's just sitting there, and not accelerating
up or down.  That means the vertical forces on it must be balanced. 

So if its weight (acting downward) is 100 newtons, then the buoyant
force on it (acting upward) must also be 100 newtons.
4 0
3 years ago
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