Insect A moves 5.0 m/min and insect B moves
1 answer:
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Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
Answer:
Explanation:
Momentum is the product of mass and velocity.
The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.
Substitute the values into the formula and multiply.
The truck's momentum is <u>70,000 kilograms meters per second.</u>