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Radda [10]
2 years ago
10

A person holding a lunch bag is moving upward in a hot air balloon at a constant speed of 7.3 m/s . When the balloon is 24 m abo

ve the ground, she accidentally releases the bag. What is the speed of the bag just before it reaches the ground?
Physics
1 answer:
Kitty [74]2 years ago
8 0

Explanation:

Given that,

Initial speed of the bag, u = 7.3 m/s

Height above ground, s = 24 m

We need to find the speed of the bag just before it reaches the ground. It can be calculated using third equation of motion as :

v^2=u^2+2as

v^2=(7.3)^2+2\times 9.8\times 24  

v=\sqrt{523.69}

v = 22.88 m/s

So, the speed of the bag just before it reaches the ground is 22.38 m/s. Hence, this is the required solution.

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If a 4 engine jet accelerates down a runway at 8.7 m/s^2, Suppose now that all 4 engins are operational on the jet from the prev
soldi70 [24.7K]

Answer:

5.22m/s^2

Explanation:

One of the first propulsion characteristics given in the example is that all engines are equal.

In this way if we have 4 engines running at the same time, it means that its capacity is 100%.

Under this premise, if 100% is found, the Jet is capable of reaching a speed of 8.7m / s ^ 2.

However, the question is, what would happen if 2.4 "Engines" now work.

To do this then we make a simple equivalence,

If 4 engines is the equivalent of 100%, when would it be 2.4 engines?

X = \frac{2.4 * 100\%} { 4 }= 60\%

In this way it would mean that the body could be driven to 60% of its total.

So

Speed_{Decreased} = 8.7 * 60\% = 5.22 \frac{m}{s^2}

3 0
2 years ago
A mass of 148 g stretches a spring 13 cm. The mass is set in motion from its equlibrium position with a downward velocity of 10
Charra [1.4K]

Answer:

u(t)=1.15 \sin (8.68t)cm

0.3619sec

Explanation:

Given that

Mass,m=148 g

Length,L=13 cm

Velocity,u'(0)=10 cm/s

We have to find the position u of the mass at any time t

We know that

\omega_0=\sqrt{\frac{g}{L}}\\\\=\sqrt{\frac{980}{13}}\\\\=8.68 rad/s

Where g=980 cm/s^2

u(t)=Acos8.68 t+Bsin 8.68t

u(0)=0

Substitute the value

A=0\\u'(t)=-8.68Asin8.68t+8.68 Bcos8.86 t

Substitute u'(0)=10

8.68B=10

B=\frac{10}{8.68}=1.15

Substitute the values

u(t)=1.15 \sin (8.68t)cm

Period =T = 2π/8.68

After half period

π/8.68 it returns to equilibruim

π/8.68 = 0.3619sec

6 0
3 years ago
The electric potential difference across the membrane of a body cell is 0.070 V (higher on the outside than on the inside). The
12345 [234]

Answer:

The electric field is 8.75 \times 10^{6}~v~m^{-1} and the ditection is from outer to inner side of the membrane.

Explanation:

We know the electric field (\vec{E}) is given by \vec{E} = - \nabla V, 'V' being the potential.

In 1-D, it can be written as

E=\dfrac{V}{d}

where 'd' is the separation of space in between the potential difference is created.

Given, V = 0.070~V~ and the thickness of the cell membrane is d = 8.0 \times 10^{-9}~m.

Therefore the created electric field through the cell membrane is

E = \dfrac{0.07~V}{8 \times 10^{-9}~m} = 8.75 \times 10^{6}~m~s^{-1}

5 0
3 years ago
Noise-canceling headphones are an application of destructive interference. Each side of the headphones uses a microphone to pick
exis [7]
The question for this problem would be the minimum headphone delay, in ms, that will cancel this noise.
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4 0
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Two firefighters are trying to break through a door. One firefighter is heavy, and the other is light. If they run at the same s
frez [133]

Answer:

The Heavier Firefighter

Explanation:

Generally, more massive objects will have more intertia than less massive objects.  As such it takes more force to halt a more massive object if its moving at the same speed as a smaller object. This can also be thought of in the context of Newton's second law. The more force needed to accelerate an object means the more force the object will have.

6 0
2 years ago
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