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Karolina [17]
3 years ago
11

A star such as the Sun starts out as a protostar with a diameter a hundred times larger than its diameter during its main-sequen

ce lifetime. Accordingly, the protostar's temperature is much less than its main-sequence temperature. Assume that while the Sun was a protostar it had a diameter 95.00 times that of the present-day Sun. How many times greater was the protostar's surface area
Physics
1 answer:
Elan Coil [88]3 years ago
8 0

The protostar's surface area was 1.1  times greater.

<h3>Surface area of the star</h3>

The surface of the star can be assumed be circular and the surface area can determined as follows;

  • initial diameter = 100d
  • final diameter = 95d

Area = πr²

Area = \frac{\pi d^2}{4} \\\\Area = \frac{(100d)^2}{(95d)^2} \\\\

Surface area = 1.1 times greater

Thus, the protostar's surface area was 1.1  times greater.

Learn more about protostars here:  brainly.com/question/891408

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What is the electric field on the surface of a thin conducting spherical shell containing uniform charge Q?
bogdanovich [222]

The field is

            <em><u>E</u></em>  =  1 / (4 pi ε₀)    Q / <em><u>R</u></em>²        directed radially outward from
                                                            the center of the shell.

R is the radius of the spherical shell.

Notice that the field is exactly the same as the field due to a point-charge
with magnitude 'Q' that's located at the center of the sphere.

3 0
4 years ago
Question 4
zysi [14]

Answer:

one of the object is at rest after the collision

3 0
2 years ago
The drawing shows three identical springs hanging from the ceiling. Nothing is attached to the first spring, whereas a 4.5 n blo
Naya [18.7K]

<Continuation of the question>

(a) the spring constant (in N/m) and

(b) the weight of the block hanging from the third spring.

the distance for the first spring is 20cm, the second 35cm, the third 50cm.

Answer:

a) To find the spring constant, we'll use the formula

F=kx, if we make k the subject we'll get

k=F/x, where F=4.5N, x = 35cm - 20cm = 15cm = 0.15m

k=F/x = 4.5N/0.15m =  30N/m is the Answer

b) to find the weight of block hanging on third spring

we use the formula F=kx

where k = 30N/m, x=50cm-20cm=30cm=0.30m

F=kx = (30N/m)*(0.30m) = 9N  is the Answer

4 0
3 years ago
A. 2kg<br><br> B. 6kg<br><br> C. 8kg<br><br> D. 14kg
Sati [7]

Answer:

A

Explanation:

We know the force is (16N-12), which is 4N, and we know the acceleration is 2 m/s^2. Meaning, we can solve the formula m = F / a (mass equals force divided by acceleration), and we get 2kg.

7 0
3 years ago
What is the frequency of a wave if the speed of the wave is 7.9m/s and the wavelength is 3.1m?​
Tpy6a [65]

Answer:

<h2>2.55 Hz</h2>

Explanation:

The frequency of the wave given it's velocity and wavelength can be found by using the formula

f =  \frac{c}{ \lambda}  \\

where

c is the velocity of the wave in m/s

\lambda is the wavelength in m

From the question

c = 7.9 m/s

\lambda = 3.1 m

We have

f  = \frac{7.9}{3.1}  = 2.548387... \\

We have the final answer as

<h3>2.55 Hz</h3>

Hope this helps you

6 0
2 years ago
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