A star such as the Sun starts out as a protostar with a diameter a hundred times larger than its diameter during its main-sequen
1 answer:
The protostar's surface area was 1.1 times greater.
<h3>Surface area of the star</h3>
The surface of the star can be assumed be circular and the surface area can determined as follows;
- initial diameter = 100d
- final diameter = 95d
Area = πr²
Surface area = 1.1 times greater
Thus, the protostar's surface area was 1.1 times greater.
Learn more about protostars here: brainly.com/question/891408
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Answer:
(a) f = 0.58Hz
(b) vmax = 0.364m/s
(c) amax = 1.32m/s^2
(d) E = 0.1J
(e) x(t)=0.1m*cos(2π(0.58s^{-1})t)
Explanation:
(a) The frequency of the oscillation, in a spring-mass system, is calculated by using the following formula:
(1)
k: spring constant = 20.0N/m
m: mass = 1.5kg
you replace the values of m and k for getting f:
The frequency of the oscillation is 0.58Hz
(b) The maximum speed is given by the following relation:
(2)
A: amplitude of the oscillations = 10.0cm = 0.10m
The maximum speed of the mass is 0.364 m/s.
The maximum speed occurs when the mass passes trough the equilibrium point of the oscillation.
(c) The maximum acceleration is given by the following formula:
The maximum acceleration is 1.32 m/s^2
The maximum acceleration occurs where the elastic force is a maximum, that is, where the mass is at the maximum distance from the equilibrium point, that is, the acceleration.
(d) The total energy of the system is calculated with the maximum potential elastic energy:
The total energy is 0.1J
(e) The displacement as a function of time is:
At 10 m/s, it will take
(2 m)/(10 m/s) = 0.2 s
to bridge the gap.
_____
However, it will take an additional 0.514 seconds (0.714 s total) for the policeman to land on the building below. The answer depends on the meaning of the question.
(2 m)/(10 m/s) = 0.2 s
to bridge the gap.
_____
However, it will take an additional 0.514 seconds (0.714 s total) for the policeman to land on the building below. The answer depends on the meaning of the question.