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Volgvan
3 years ago
9

If the force of the sun and the earth is 3.5×10 to the power of 22 N, how far apart are they?

Physics
1 answer:
Jobisdone [24]3 years ago
5 0

Gravitational force between 2 objects . . .

F = G · m₁ · m₂ / D²

-- You said that F = 3.5 x 10²² Newtons.

-- G = the gravitational constant = 6.67 x 10⁻¹¹ N m² / kg²

-- You want to find D .

F = G · m₁ · m₂ / D²

Multiply each side by D² . . .  D² · F = G · m₁ · m₂

Divide each side by F . . .  D² = G · m₁ · m₂ / F

So finally . . . D = √(G · m₁ · m₂ / F )

D = √(6.67 x 10⁻¹¹ N·m²/kg² · Earth mass · Sun mass / 3.5 x 10²² N)

<em>D = 4.37 x 10⁻¹⁷ · √(Earth mass · Sun mass) </em> meters

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Answer:

Fn: magnitude of the net force.

Fn=30.11N , oriented 75.3 ° clockwise from the -x axis

Explanation:

Components on the x-y axes of the 17 N force(F₁)

F₁x=17*cos48°= 11.38N

F₁y=17*sin48° = 12.63 N

Components on the x-y axes of the  the second force(F₂)

F₂x= −19.0 N

F₂y=   16.5 N

Components on the x-y axes of the net force (Fn)

Fnx= F₁x +F₂x= 11.38N−19.0 N= -7.62 N

Fny= F₁y +F₂y= 12.63 N +16.5 N = 29.13 N

Magnitude of the net force.

F_{n} =\sqrt{(F_{nx})^{2} +(F_{ny}) ^{2} }

F_{n} =\sqrt{(-7.62)^{2} +(29.13) ^{2} }

F_{n} = 30.11N

Direction of the net force (β)

\beta =tan^{-1} (\frac{29.13}{7.62} )

β=75.3°

Magnitude and direction of the net force

Fn= 30.11N , oriented 75.3 ° clockwise from the -x axis

In the attached graph we can observe the magnitude and direction of the net force

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c

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Your answer is on the inside bends!

When rocks are deposition on the bottom of the river pressure can cause the rock to break down in sentiments!

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