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2 years ago

If the force of the sun and the earth is 3.5×10 to the power of 22 N, how far apart are they?

Physics

1 answer:

Jobisdone [24]2 years ago

5 0

Gravitational force between 2 objects . . .

F = G · m₁ · m₂ / D²

-- You said that F = 3.5 x 10²² Newtons.

-- G = the gravitational constant = 6.67 x 10⁻¹¹ N m² / kg²

-- You want to find D .

F = G · m₁ · m₂ / D²

Multiply each side by D² . . . D² · F = G · m₁ · m₂

Divide each side by F . . . D² = G · m₁ · m₂ / F

So finally . . . D = √(G · m₁ · m₂ / F )

D = √(6.67 x 10⁻¹¹ N·m²/kg² · Earth mass · Sun mass / 3.5 x 10²² N)

<em>D = 4.37 x 10⁻¹⁷ · √(Earth mass · Sun mass) </em> meters

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$d=2.0467(10)^{-10}m$ (4)

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$r=0.10233nm$ This is the radius of the helium atom in nanometers.

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