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2 years ago

Grilled cheese or Cheese toasty??

Physics

2 answers:

LUCKY_DIMON [66]2 years ago

6 0

Answer:

Toasties are British in origin and were usually made in ovens. They were the same as a grilled cheese but the bread was not buttered. Some Brits would make them in a pan in the oven, too, which is even closer to the stove-top grilled cheese.

jarptica [38.1K]2 years ago

4 0

Answer: grilled cheese lol

Explanation:

You might be interested in

Excellent human jumpers can leap straight up to a height of

Firlakuza [10]

For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.

We can calculate the initial speed to reach 110 cm of height with the following equation:

$v_{f}^{2} = v_{i}^{2} - 2gh$

Where:

$v_{f}$ : is the final speed = 0 (at the maximum height of 110 cm)

$v_{i}$ : is the initial speed =?

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 110 cm = 1.10 m

Hence, the initial velocity is:

$v_{i} = \sqrt{v_{f}^{2} + 2gh} = \sqrt{2*9.81 m/s^{2}*1.10 m} = 4.65 m/s$

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.

You can see another example here: brainly.com/question/13359681?referrer=searchResults

I hope it helps you!

4 0

2 years ago

A new planet has been discovered and given the name Planet X . The mass of Planet X is estimated to be one-half that of Earth, a

harina [27]

Answer:

vₐ = v_c $( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )$

Explanation:

To calculate the escape velocity let's use the conservation of energy

starting point. On the surface of the planet

Em₀ = K + U = ½ m v_c² - G Mm / R

final point. At a very distant point

Em_f = U = - G Mm / R₂

energy is conserved

Em₀ = Em_f

½ m v_c² - G Mm / R = - G Mm / R₂

v_c² = 2 G M (1 /R - 1 /R₂)

if we consider the speed so that it reaches an infinite position R₂ = ∞

v_c = $\sqrt{\frac{2GM}{R} }$

now indicates that the mass and radius of the planet changes slightly

M ’= M + ΔM = M ( $1+ \frac{\Delta M}{M}$ )

R ’= R + ΔR = R ( $1 + \frac{\Delta R}{R}$ )

we substitute

vₐ = $\sqrt{\frac{2GM}{R} } \ \frac{\sqrt{1+ \frac{\Delta M}{M} } }{ \sqrt{1+ \frac{ \Delta R}{R} } }$

let's use a serial expansion

√(1 ±x) = 1 ± ½ x +…

we substitute

vₐ = v_ c ( $(1 + \frac{1}{2} \frac{\Delta M}{M} ) \ ( 1 - \frac{1}{2} \frac{\Delta R}{R} )$ )

we make the product and keep the terms linear

vₐ = v_c $( \ 1 + \frac{1}{2} ( \frac{\Delta M}{M} - \frac{\Delta R}{R}) \ )$

5 0

2 years ago

What is the relationship between force and motion described by Newton's first law

prisoha [69]

Newtons First Law of Motion:
An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

Therefore, the relationship between force and motion is that it takes force to change the speed or direction of any object in motion.

4 0

3 years ago

Increasing the amount of current that flows through a wire ______ the strength of an electromagnet

Anestetic [448]

Electromagnet is in form of solenoid

and the magnetic field due to solenoid is given as

$B = \mu_0 n i$