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igomit [66]
3 years ago
8

If a fluid has high viscosity, does it flow faster or slower than a fluid with less viscosity?

Physics
2 answers:
Zinaida [17]3 years ago
4 0

It will flow SLOWER than a fluid with less viscosity.

diamong [38]3 years ago
4 0

Viscosity is thick goopiness.

Water, vinegar, orange juice, and gasoline have low viscosity.

Molasses and honey have high viscosity.

Also ... strange as it may seem ... <em>glass </em>is a liquid with huge viscosity.

Fluids with high viscosity flow <em>slower </em>than fluids with less viscosity.

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Something has a mass of 40 kg and a velocity of 1 m/s
lesantik [10]
  • m=40kg
  • v=1m/s

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2

\\ \sf\Rrightarrow K.E=20J

<h3>Part 2:-</h3>
  • m=80kg

\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2

\\ \sf\Rrightarrow K.E=40J

  • Yes
6 0
3 years ago
A tube is sealed at both ends and contains a 0.0100-m long portion of liquid. The length of the tube is large compared to 0.0100
Ahat [919]

Answer:

31.321 rad/s

Explanation:

L = Tube length

A = Area of tube

\rho = Density of fluid

v = Fluid velocity

m = Mass = \rho Al

Centripetal force is given by

F=\dfrac{mv^2}{L}\\ F=\dfrac{m(\omega L)^2}{L}\\ F=m\omega^2\\ F= 0.01A\rho\omega^2L

Pressure is given by

P=\dfrac{F}{A}=\rho gL\\\Rightarrow \dfrac{0.01A\rho\omega^2L}{A}=\rho gL\\\Rightarrow 0.01\omega^2=g\\\Rightarrow \omega^2=\dfrac{g}{0.01}\\\Rightarrow \omega=\sqrt{\dfrac{g}{0.01}}\\\Rightarrow \omega=\sqrt{\dfrac{9.81}{0.01}}\\\Rightarrow \omega=31.321\ rad/s

The angular speed of the tube is 31.321 rad/s

5 0
3 years ago
A parachute on a drag race car opens and changes the velocity of the car from 75 m/s to 45 m/s in 8 seconds. Calculate the avera
nikdorinn [45]
Buscalo en gugal byy
3 0
3 years ago
A device is rated at 1.3kW when connected to a 120 V source. The equivalent resistance of this device in ohm is:
alexdok [17]

Answer:

D.

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7 0
3 years ago
) A 100-g ball falls from a window that is 12 m above ground level and experiences no significant air resistance as it falls. Wh
yawa3891 [41]

Answer:

Momentum = 1.534 kgm/s

Explanation:

Using the equations of motion, we can obtain the velocity of the ball as it hits the ground.

g = 9.8 m/s²

y = 12 m

u = initial velocity = 0 m/s, since the ball was released from rest

v = final velocity befor the ball hits the ground.

v² = u² + 2ay

v² = 0 + 2×9.8×12 = 235.2

v = 15.34 m/s

The momentum at any point is given as mass × velocity at that point

Mass = 100 g = 0.1 kg, velocity = 15.34 m/s

Momentum = 0.1 × 15.34 = 1.534 kgm/s

3 0
4 years ago
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