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3 years ago

Which statement BEST describes acceleration?

1 answer:

3 0

C) Acceleration is the rate of change of velocity of an object. Velocity is the speed and direction of an object so acceleration is used to describe the rate of change. I hope this helps!!

You might be interested in

In AA&E storage facilities, why must drainage structures be secured if they cross the fence line and meet certain size requi

Likurg_2 [28]

Answer:

As an additional security measure in an AA&E storage facilities, securing drainage structures must be considered if their cross section is greater than 96 inches and any dimension is greater than 6 inches, they must be barred and welded at the intersections to prevent any human from crawling into the area.

Explanation:

U.S. national security relys on ensuring DoD sensitive or classified assets such as classified material, arms, ammunition, and explosives (AA&E) and nuclear weapons, in properly safeguard facilites and storage containers, voiding DoD assets loss or compromise and additional to supplemental intrusion detection systems and guard patrols, security lighting, communications, fences and clear zones, drainage structures, key control, and other security measures required to protect AA&E.

6 0

3 years ago

Potential energy is sometimes called?

Serhud [2]

Answer:

it can be called PE or sometimes, there are equations which you can use the letter U.

Explanation:

4 0

3 years ago

Read 2 more answers

A meteor is

Leya [2.2K]

Answer:

A meteor is B) an icy body with a long tail extending from it.

Explanation:

Meteors are very small dust particles that, when penetrating into the Earth's atmosphere, burn quickly by rubbing with the gases of the same. Some meteors, those with larger dimensions and appreciable weights, are brighter and can describe longer trajectories, showing longer.

In other words, the meteoroids, celestial bodies can vary in size between 100 micrometers up to 50 meters, they collide with the atmosphere of our planet and if the particles are of a small size, upon impact they enter combustion creating a flash, is what we know as meteor or shooting star. Therefore, the meteor is a luminous phenomenon that leaves behind a persistent trail.

So, <u><em>a meteor is B) an icy body with a long tail extending from it.</em></u>

4 0

3 years ago

In an Atwood machine the two masses (m1 =5.0kg and m2 = 3.0 kg) are released from rest, with m1 at a height of h=0.75 m above th

masya89 [10]

Answer:

Explanation:

m₁ is heavy so it will go down and m₂ will go up. Let common acceleration be a .

For downward acceleration of m₁

m₁g - T₁ = m₁a

For upward acceleration of m₂

T₂- m₂g = m₂a

adding

m₁g - T₁ +T₂- m₂g = (m₁+m₂)a

m₁g- m₂g +(T₂- T₁) = (m₁+m₂)a --------------- ( 1 )

For rotatory motion of disc of mass mp and moment of inertia I

(T₁ -T₂ )R = I α , α is angular acceleration ----------( 2 )

From 1 and 2

m₁g- m₂g - I α / R = (m₁+m₂)a

m₁g- m₂g - I a / R² = (m₁+m₂)a

m₁g- m₂g = (m₁+m₂)a + I a / R²

m₁g- m₂g = [(m₁+m₂) + mp k² / R² ] a ( k is radius of gyration of disk )

a = (m₁- m₂)g / [(m₁+m₂) +mp k² / R² ]

= (m₁- m₂)g / [(m₁+m₂) + .5 mp ] ( for cylinder k² / R² = .5 )

If h be the height by which m₁ falls and its velocity becomes v

v² = 2 a h

a = v² / 2h

v² / 2h = (m₁- m₂)g / [(m₁+m₂) + .5 mp ]

v²[(m₁+m₂) + .5 mp ] = 2(m₁- m₂) gh

- v²[(m₁+m₂) +2(m₁- m₂) gh = .5 mp v²

- v²[(m₁+m₂) +2(m₁- m₂) gh / .5 v ² = mp .

- 1.8² ( 5 + 3 ) + 2 ( 5 - 3 ) 9.8 x .75 / .5 x 1.8² = mp

- 25.92 + 29.4 / 1.62 = mp

2.15 kg = mp .

K.E of masses = 1/2 x 5 x 1.8² + 1/2 x 3 x 1.8²

= 12.96 J

Rotational KE of disc

= 1/2 I ω²

= 1/4 mp r²ω²

= 1/4 x mp x v²

= .25 x 2.15 x 1.8²

= 1.74 J

in percent terms

(1.74 / 12.96) x 100

= 13.5 %

5 0

3 years ago

The work function for a photosensitive metal is 1.5 eV. The metal is illuminated with a light of wavelength 500 nm. Find: (a) ma

nlexa [21]

A) We want to find the maximum kinetic energy of the photoelectrons.

E = 1243/λ - Φ

E = kinetic energy of photoelectrons, λ = light wavelength, Φ = work function

Given values:

λ = 500nm, Φ = 1.5eV

Plug in and solve for E:

E = 1243/500 - 1.5

E = 0.986eV

B) We want to find the maximum speed of the photoelectrons.

KE = 0.5mv²

KE = max kinetic energy, m = electron mass, v = max speed

Given values:

KE = 0.986eV = 1.58×10⁻¹⁹J, m = 9.11×10⁻³¹kg

Plug in and solve for v:

1.58×10⁻¹⁹ = 0.5(9.11×10⁻³¹)v²

v = 5.89×10⁵m/s

C) We want to find the stopping potential for the photoelectrons:

Vq = E

V = stopping potential, q = electron charge, E = max kinetic energy of photoelectrons

Given values:

q = e (elementary charge), E = 0.986eV

There isn't much work to do to find V. The energy E is already given in electron-volts which is defined as the amount of energy an electron gains when passed through a 1V potential difference. All you have to do is remove the "e" from "eV" and you'll have your answer.

V = 0.986V

4 0

3 years ago