1.302 moles of carbon dioxide would have to be added
<h3>Further explanation</h3>The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient
The equilibrium constant is based on the concentration (Kc) in a reaction
pA + qB -----> mC + nD
While the equilibrium constant is based on partial pressure
The value of Kp and Kc can be linked to the formula '
R = gas constant = 0.0821 L.atm / mol.K
=n = number of product coefficients-number of reactant coefficients
An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O
Reaction :
CO +H₂O ⇔ CO₂ + H₂
initially 0.2 0.2 0.75+x 0.75
reaction 0.1 0.1 0.1 0.1
product 0.3 0.3 0.65+x 0.65
an equilibrium constant brainly.com/question/9173805
Calculate the value of the equilibrium constant, Kc
Concentration of hi at equilibrium
Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient
Answer:
Explanation:
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In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:
As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:
Thus, by plugging in the data, we obtain:
Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:
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