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TiliK225 [7]
3 years ago
13

19. 4.0 L of a gas at 1.0 atm is compressed into a 0.85 L cylinder. What is the pressure of the compressed gas if

Chemistry
1 answer:
Neko [114]3 years ago
4 0

Answer:

The correct answer is d. 4.7 atm

Explanation:

We apply Boyle Mariotte's law, where for a certain mass of gas at constant temperature, the pressure and temperature vary inversely proportionally: P1xV1 = P2xV2

P2= (P1xV1)/V2= (1,0 atm x 4,0 L)/0,85L= <em>4, 705882353 atm</em>

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What happens in a single-replacement reaction?
antoniya [11.8K]

Answer:

D

Explanation:

A single-replacement reaction occurs when one element replace another in a single compound.

8 0
3 years ago
What is the empirical formula of a compound which contains 84.4% c and 15.6% h by mass?
podryga [215]

Answer: The empirical formula for the given compound is CH_2

Explanation : Given,

Percentage of C = 84.4 %

Percentage of H = 15.6 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 84.4 g

Mass of H = 15.6 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{84.4g}{12g/mole}=7.03moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{15.6g}{1g/mole}=15.6moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.03 moles.

For Carbon = \frac{7.03}{7.03}=1

For Hydrogen  = \frac{15.6}{7.03}=2.22\approx 2

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 2

Hence, the empirical formula for the given compound is C_1H_2=CH_2

7 0
3 years ago
How many hydrogen atom are present in 1.53 g of water
svp [43]

Answer:

=1.02x10^{23} atoms\ H

Explanation:

Hello,

In this case, for water, whose molar mass is 18 g/mol, we can find two moles of hydrogen in one mole of water, therefore, for us compute the atoms, we should also use the Avogadro's number as shown below:

=1.53gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} *\frac{6.022x10^{23}atoms\ H}{1molH} \\\\=1.02x10^{23} atoms\ H

Regards.

3 0
3 years ago
5.5 x 10^23 molecules of CO is dissolved in 222ml of water to have what molarity?
steposvetlana [31]

Answer:

nichuhh

Explanation:

4 0
3 years ago
When energy is transformed, some is wasted. What is a common form of wasted energy in some energy transformations? (Think about
tresset_1 [31]

Answer:

Eletrical

Explanation:

The electric transfers 70% of the input energy to kinetic energy 30% is wasted output energy in the form of thermal energy and sound.

4 0
3 years ago
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