The answer is A. ive done a 5-k race, so its for sure 3 miles.
The final velocity is +15.0 m/s
Explanation:
The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:

where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the cart in this problem, we have:
u = +3.0 m/s (initial velocity)
(acceleration)
t = 8.0 s (time)
Substituting, we find the final velocity:

Learn more about accelerated motion:
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Answer:
<h2>
36cm from the surface</h2>
Explanation:
Equation of refraction of a lens is expression according to the formula given below;

R is the radius of curvature of the convex refracting surface = 12cm
v is the image distance from the refracting surface
u is the object distance from the refracting surface
n₁ and n₂ are the refractive indices of air and the medium respectively
Given parameters
R = 12 cm
u =
(since light incident is parallel to the axis)
n₁ = 1
n₂ = 1.5
Required
<em>focus point of the light that is incident and parallel to the central axis (v)</em>
<em />
Substituting this values into the given formula we will have;

Cross multiply

Hence Light incident parallel to the central axis is focused at a point 36cm from the surface
Calculating speed as function of distance y is fairly easy. Once water leaves pipe it is under free fall which means that it is accelerating with gravitational acceleration "a".
V=Vo + Vff where Vff is speed gained due to free fall.


Calculating radius of stream is a little bit more complicated. Because water is accelerating as it falls it has to lower its radius. The reason for this is that water flow must be the same as one at the exit of pipe. Water flow is expressed in liters/meter^3
Because of this we write condition:
V1/V2 = A2/A1 where A2 and A1 are sections of water stream.
let V1 and A1 be the speed and section of water stream at the end of pipe.
A2 = V1*A1/V2
Answer:
Β. 16 με
Explanation:
Data provided in the question
Number of electrons removed = 10^14
And, the charge on one electron = 
Based on the above information, the charged on the sphere is
Therefore when we remove the electrons
So, the equation would be

= 
Therefore the same amount of the positive charged would be developed
Hence, the correct option is B.