1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
velikii [3]
3 years ago
14

g The tires of a car make 75 revolutions as the car reduces its speed uniformly from 91 km/h to 48 km/h . The tires have a diame

ter of 0.78 m . Part A What was the angular acceleration of the tires
Physics
1 answer:
aleksandrvk [35]3 years ago
5 0

Answer:

   α = -0.01625 rad / s²

Explanation:

This is an exercise in angular kinematics, we can use the relation

         w = w₀ + 2 α θ

linear and angular variables are related

        v = w r

         w = v / r

Let's reduce the magnitudes to the SI system

         v₀ = 91 km / h (1000m / 1km) (1h / 3600s) = 25.278 m / s

         v = 48 km / h = 13,333 m / s

         θ  = 75 rev (2π rad / 1 rev) = 471.24 rad

Let's find the angular velocities

         w₀ = v₀ / r

         w₀ = 25.278 / 0.78

         w₀ = 32,408 rad / s

         w = v / r

         w = 13.333 / 0.78

         w = 17.09 rad / s

we calculate the angular acceleration

         α = (w- w₀) / 2θ  

         α = (17.09 - 32.408) / (2 471.24)

         α = -0.01625 rad / s²

the negative sign indicates that the wheel is stopping

You might be interested in
Which the answer It's science
earnstyle [38]
The answer is A. ive done a 5-k race, so its for sure 3 miles. 
3 0
3 years ago
a cart's initial velocity is +3.0 meters per second. What is its final velocity after accelerating at a rate of 1.5m/s2 for 8.0
Andreas93 [3]

The final velocity is +15.0 m/s

Explanation:

The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:

v=u+at

where

v is the velocity at time t

u is the initial velocity

a is the acceleration

t is the time

For the cart in this problem, we have:

u = +3.0 m/s (initial velocity)

a=1.5 m/s^2 (acceleration)

t = 8.0 s (time)

Substituting, we find the final velocity:

v=3.0+(1.5)(8.0)=+15.0 m/s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

4 0
3 years ago
A convex refracting surface has a radius of 12 cm. Light is incident in air (n = 1) and refracted into a medium with an index of
OLga [1]

Answer:

<h2>36cm from the surface</h2>

Explanation:

Equation of refraction of a lens is expression according to the formula given below;

\dfrac{n_2}{v} = \dfrac{n_1}{u}=  \dfrac{n_2-n_1}{R}

R is the radius of curvature of the convex refracting surface = 12cm

v is the image distance from the refracting surface

u  is the object distance from the refracting surface

n₁ and n₂ are the refractive indices of air and the medium respectively

Given parameters

R = 12 cm

u = \infty (since light incident is parallel to the axis)

n₁  = 1

n₂  = 1.5

Required

<em>focus point of the light that is incident and parallel to the central axis (v)</em>

<em />

Substituting this values into the given formula we will have;

\dfrac{1.5}{v} - \dfrac{1}{\infty}=  \dfrac{1.5-1}{12}\\\\\dfrac{1.5}{v} -0=  \dfrac{0.5}{12}\\\\\dfrac{1.5}{v}=  \dfrac{0.5}{12}\\\\

Cross multiply

1.5*12 = 0.5*v\\ \\18 = 0.5v\\\\v = \frac{18}{0.5}\\ \\v = 36cm

Hence  Light incident parallel to the central axis is focused at a point 36cm from the surface

6 0
2 years ago
A liquid flowing from a vertical pipe has a very definite shape as it flows from the pipe. To get the equation for this shape, a
Eva8 [605]
Calculating speed as function of distance y is fairly easy. Once water leaves pipe it is under free fall which means that it is accelerating with gravitational acceleration "a".
V=Vo + Vff   where Vff is speed gained due to free fall.
Vff = t*a =  \sqrt{2ay}
V = Vo +  \sqrt{2ay}

Calculating radius of stream is a little bit more complicated. Because water is accelerating as it falls it has to lower its radius. The reason for this is that water flow must be the same as one at the exit of pipe. Water flow is expressed in  liters/meter^3
Because of this we write condition:
V1/V2 = A2/A1 where  A2 and A1 are sections of water stream.
let V1 and A1 be the speed and section of water stream at the end of pipe.
A2 = V1*A1/V2

r^{2}  = \frac{Vo*  r_{0} ^{2} }{Vo+ \sqrt{2ay} }
4 0
3 years ago
Read 2 more answers
3. When 10^14 electrons are removed from a neutral metal sphere, the charge on the sphere
Umnica [9.8K]

Answer:

Β. 16 με

Explanation:

Data provided in the question

Number of electrons removed = 10^14

And, the charge on one electron = 1.6\times 10^ {-19C}

Based on the above information, the charged on the sphere is

Therefore when we remove the electrons

So, the equation would be

10^{14} \times 1.6 \times 10^{-19 C}

= 1.6 \times 10

Therefore the same amount of the positive charged would be developed

Hence, the correct option is B.

4 0
3 years ago
Other questions:
  • You have a remote-controlled car that has been programmed to have velocity v⃗ =(−3ti^+2t2j^)m/s, where t is in s. At t = 0 s, th
    5·1 answer
  • a 4kg block is attatched to a vertical sspring constant 800n/m. the spring stretches 5cm down. how much elastic potential energy
    11·1 answer
  • Elements that easily transmit electricity and heat display the property known as conductivity.
    12·2 answers
  • A throttle position sensor waveform is going to be observed. At what setting should the volts per division be set to see the ent
    11·1 answer
  • What happens to the entropy of a piece of wood as it is burned?
    10·1 answer
  • Once an object enters orbit, what keeps the object moving sideways?
    8·2 answers
  • Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012 W) pu
    8·1 answer
  • A charge of 4.4 10-6 C is located in a uniform electric field of intensity 3.9 105 N/C. How much work (in Joules) is required to
    9·1 answer
  • You are taking an image of a patient who is in extreme discomfort while participating in the CT scanning process. Which of the f
    10·1 answer
  • If the car is traveling at a velocity of 15 m/s, what is the approximate centripetal acceleration of the car?.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!