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3 years ago

The chart shows the power ratings of 3 clothes dryers and the time needed to dry a load of 10 towels.

Physics

1 answer:

atroni [7]3 years ago

6 0

Answer:

12010

Explanation:

Given:

power time

4,370 25

4,420 22

4,150 26

To find: difference in energy used between the dryer that uses the greatest amount of energy and the dryer that uses the least amount

Solution:

Energy = power × time

For clothes dryer x:

energy = 4370 × 25 = 109250

For clothes dryer y:

energy = 4420 × 22 = 97240

For clothes dryer z:

energy = 4150 × 26 = 107900

Dryer x uses the greatest amount of energy and dryer y uses the least amount of energy.

Difference in energy used between the dryer that uses the greatest amount of energy and the dryer that uses the least amount = 109250 - 97240 = 12010

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A water pipe tapers down from an initial radius of R1 = 0.21 m to a final radius of R2 = 0.11 m. The water flows at a velocity v

Aleks [24]

Answer:

$0.116 m^3/s$

Explanation:

The volume flow rate of a fluid in a pipe is given by:

$Q=Av$

where

A is the cross-sectional area of the pipe

v is the speed of the fluid

In this problem, at the initial point we have

v = 0.84 m/s is the speed of the water

r = 0.21 m is the radius of the pipe, so the cross-sectional area is

$A=\pi r^2 = \pi (0.21 m)^2 =0.138 m^2$

So, the volume flow rate is

$Q=(0.138 m^2)(0.84 m/s)=0.116 m^3/s$

8 0

4 years ago

Determine the index of refraction of glass that is struck by unpolarized light at 53.8 degrees and resulting in a fully polarize

nignag [31]

Answer:

The refractive index of glass, $\mu_{g} = 1.367$

Solution:

Brewster angle is the special case of incident angle that causes the reflected and refracted rays to be perpendicular to each other or that angle of incident which causes the complete polarization of the reflected ray.

To determine the refractive index of glass:

$tan\theta_{P} = \frac{\mu_{g}}{\mu_{a}}$ (1)

where

$\mu_{a}$ = refractive index of glass

$\mu_{g}$ = refractive index of glass

Now, using eqn (1)

$tan{53.8^{\circ}} = \frac{\mu_{g}}{1}$

$\mu_{g} = tan53.8^{\circ}$

$\mu_{g} = 1.367$

5 0

3 years ago

If the wavelength of a wave is quadrupied then what happens to the frequency of the wqve(Assume speed is constant)

dimulka [17.4K]

Answer:

What happens to the wavelength of a wave if you double the frequency?

If the frequency of a wave is increased, what happens to its wavelength? As the frequency increases, the wavelength decreases. 2. If the frequency is doubled, the wavelength is only half as long.

Explanation:

4 0

3 years ago

A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in

Scrat [10]

Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

for the first one: 

f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

m1=2

for the second one :

f=m2×a

20=m2×5

m2= 20/5

m2= 4

since F=ma

F=(m1+m2) ×a

F =(4+2)×a

F =6×a

F=20(from the question above )

20=6×a

a=20/6

a=3.33

8 0

4 years ago

Read 2 more answers

An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work mu

Maru [420]

The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.

Given:

Potential difference, V = 1.2 V

Charge on an electron, e = 1.6 × 10⁻¹⁹ C

Calculation:

We know that the work done to transport an electron from the positive to the negative terminal is given as:

W.D = (Charge on electron)×(Potential difference)

= e × V

= (1.6 × 10⁻¹⁹ C)×(1.2 V)

= 1.92 × 10⁻¹⁹ J

Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.

Learn more about work done on a charge here:

brainly.com/question/13946889

#SPJ4

4 0

2 years ago