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sergeinik [125]
4 years ago
9

A spinning ice skater on extremely smooth ice is able to control the rate at which she rotates by pulling in her arms. Which of

the following statements are true about the skater during this process? (There could be more than one correct choice.)
Her kinetic energy remains constant.
Her moment of inertia remains constant.
Her angular momentum remains constant.
She is subject to a constant non-zero torque.
Physics
1 answer:
Korvikt [17]4 years ago
7 0

Answer:

Correct -> Her angular momentum remains constant.

Explanation:

If the skater pulls her arms, her radius changes, so her moment of inertia changes.

By definition, moment of inertia is the resistance to rotation. So, if her moment of inertia decreases, her angular velocity increases, because if there is no external torque (in this question there is none), angular momentum is conserved.

L = I\omega

K = \frac{1}{2}I\omega^2

If the moment of inertia decreases by half, the angular velocity doubles. In that case kinetic energy also increases, because the square of the angular velocity affects the kinetic energy more than the decrease of the moment of inertia.

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4 years ago
How much energy is stored in the electric field of a 50-μm-diameter cell with a 7.0-nm-thick cell wall whose dielectric constant
Anastaziya [24]
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You already have your separation and dielectric constant so just use the formula you stated towards the end of your question and you get 8.93x10^-11 Farads which is about 89pF</span>
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4 years ago
Read 2 more answers
In a particular region, there is a uniform magnetic field with a magnitude of 2.00 T. You take a particle with a charge of +6.00
expeople1 [14]

Answer:

a) 1.68 N b) 0 c) 14.5º

Explanation:

a)

  • The force on a charge moving in a magnetic field, is a vector perpendicular to the plane defined by the velocity of the charge and the magnetic field.
  • The magnitude of the force F is given by the following expression:

       F = q*v*B*sin\theta (1)

  • where q= magnitude of the charge of the particle, v=velocity of the particle, B= magnitude of the magnetic field, and θ= angle between v and B.
  • Replacing by the known values in (1) we have:

       F = q*v*B*sin\theta (1) = 6.00e-6C*1.40e5m/s*2T*sin\theta=\\ \\ F= 1.68N*sin\theta

  • The maximum possible value of F happens when sin θ =1
  • This means that v and B are perpendicular each other (in the same plane)
  • So, Fmax = 1.68 N

b)

  • If the maximum possible value of F happens when sin θ = 1, the minimum possible is when sin θ = 0.
  • In this case, when v  and B are parallel each other, the force is just 0.

c)

  • If the force is 0.25 of the maximum possible, (which is when sin θ =1), this means that sin θ = 0.25, as it can be seen below:

       F_{\theta} = q*v*B*sin \theta = 0.25*Fmax\\ F_{\theta} = q*v*B*sin\theta= 0.25 (q*v*B*sin 90) \\ sin \theta = 0.25

       \theta = sin^{-1} (0.25) =14.5 deg

  • The angle between the velocity v and the magnetic field B is 14.5º.
3 0
4 years ago
Algunas fabricas de balones de fútbol ubicadas en la costa inflan los balones que van a ser vendiéndose las ciudades como pasto,
otez555 [7]

Answer:

balloon is rigid the amount of gas is constant inside the interior pressure of the balloon is constant and in these cities it becomes equal to or slightly higher than atmospheric pressure

Explanation:

Este ejercicio es referente a la mecánica de fluidos, usemos la expresión para la presión  

       P = ρ g h

En es el caso del balón  usemos la presión en la pared extrema, llamemos P la presión por el gas en el interior y P_ext la presión atmosférica del lugar

        cuando se llena el valor en una ciudad de baja altura la presión atmosférica es mas alta

          P_int1 < P_ext1

por lo cual la pared del balón no se mantiene rígida.

Cuando el balón es trasladado a una ciudad con mayor altura sobre el nivel del mar la presión exterior disminuye

       P_ext2 = ρ g h₂ < P_ext1

en promedio la presión disminuye con la altura  en 0,029 atm cada 250 m

por lo tanto como la cantidad de gas es constante en el interior la presión interior del globo es constante y en esta ciudades se hace igual o un poco mayor que la presión atmosférica, en consecuencia la pared del globo esta rígida

        P_int2 >P_ext2

Traslate

This exercise is related to fluid mechanics, let's use the expression for pressure

       P = ρ g h

In the case of the balloon, let's use the pressure on the extreme wall, let's call P the pressure for the gas inside and P_ext the atmospheric pressure of the place

        when the value is filled in a low-lying city the atmospheric pressure is higher

          P_int1 <P_ext1

therefore the wall of the ball does not remain rigid.

When the ball is transferred to a city with higher altitude above sea level, the external pressure decreases

       P_ext2 = ρ g h <P_ext1

on average the pressure decreases with height by 0.029 atm every 250 m

therefore as balloon is rigid the amount of gas is constant inside the interior pressure of the balloon is constant and in these cities it becomes equal to or slightly higher than atmospheric pressure, therefore the wall of the

        Pint 2> Pe

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PIT_PIT [208]

Answer:

c. that light can travel in a vacuum

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