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s2008m [1.1K]
3 years ago
15

A rock has a specific gravity of 2.32 and a volume of 8.64 in3 how much does it weigh

Physics
1 answer:
lianna [129]3 years ago
3 0

Answer: 3.21 N

Specific\hspace{1mm} gravity = \frac {Density\hspace{1mm}of\hspace{1mm}substance}{Density\hspace{1mm} of \hspace{1mm}water}

\Rightarrow Density \hspace{1mm}of\hspace{1mm}substance= 2.32\times 1000\hspace{1mm} kg/m^3 = 2320\hspace{1mm}kg/m^3\\ Mass =Density\times volume\\ \Rightarrow 2320 \hspace{1mm} kg/m^3\times 8.64 \hspace{1mm}in^3\times \frac {1.64\times10^{-5} m^3}{1\hspace{1mm}in^3}=0.328 kg

For weight, we will multiply by g=9.8 m/s^{-2}

weight= 0.328\times9.8=3.21\hspace{1mm}N

Hence, the rock would weigh 3.21 N.

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Answer:

Neither A or B

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3 years ago
Which of the following are features of the nucleus of an atom
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Jenny is studying a compound that has two oxygen atoms and one nitrogen atom. Which statement describes the subscripts she will
STALIN [3.7K]

Answer:

She will use one 2 as a subscript.

Explanation:

Nitrogen is a chemical element with the symbol "N" and has an atomic number of 7. Thus, it is found in group (5) of the periodic table and as such it has 5 electrons in its outermost shell. Therefore, nitrogen has two (5) valence electrons.

On the other hand, oxygen has an atomic number of 8 and with the symbol "O."

When nitrogen and oxygen react chemically, they produce a compound known as nitrogen dioxide NO_{2}

In this scenario, Jenny is studying a compound that has two oxygen atoms and one nitrogen atom. Therefore, the statement which describes the subscripts she will use to write the chemical formula is, she will use one 2 as a subscript.

N + O_{2} ------>  NO_{2}

Where: 2 represents the subscript of oxygen.

7 0
3 years ago
A wave with a frequency of 325 Hz. is travelling at a speed of 125 m/s. What is the wavelength of this wave?
ollegr [7]

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0.385 meters

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I always remember it as "Velma is Waving Frantically"

So, 125=(wavelength)*(325)

Therefore, wavelength=0.385 meters!

Hope this helped!

4 0
3 years ago
A real power supply can be modeled as an ideal EMF of 60 Volts in series with an internal resistance. The voltage across the ter
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5 ohms

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Given:

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Now, we know that, the voltage drop in the battery is given as:

V_d=Ir

Therefore, the voltage across the terminals of the battery is given as:

V= E-V_d\\\\V=E-Ir

Now, rewriting in terms of 'r', we get:

Ir=E-V\\\\r=\frac{E-V}{I}

Plug in the given values and solve for 'r'. This gives,

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Therefore, the internal resistance of the battery is 5 ohms.

5 0
3 years ago
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