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Vedmedyk [2.9K]
3 years ago
10

A 20-kg cart travels at 20 m/s in a circle with a radius of 20 m. What is the centripetal force?

Physics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

The equation for centripetal force is:

T = (mv^2)/r

T = centripetal force

m = mass

v = speed

r = radius

T = [20kg * (20 m/s * 20m/s)] / 20 m

T = [20kg * 400 m/s^2] / 20 m

T = 8,000 kg m/s^2 / 20 m

T = 400 N

Explanation:

Vlad1618 [11]3 years ago
5 0

Centripetal force = (mass) x (speed)² / (radius)

                           = (20 kg) x (20 m/s)² / (20 m)

                           = (20 x 20 / 20)  (kg-meter/sec²)

                           = 20 newtons


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A train at a constant 60.0 km/h moves east for 40.0 min, then in a direction 50.0 degrees east of due north for 20.0 min, and th
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Answer:

Part a)

v = 7.57 km/h

Part b)

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now it turns towards 50 degree East of North

so its distance is given as

d_2 = 20 km(sin50 \hat i + cos50\hat j)

d_2 = 15.3 \hat i + 12.8 \hat j

then finally it moves towards west for 50 min

d_3 = -50 \hat i

Now the total displacement of the train is given as

d = d_1 + d_2 + d_3

d = (40 + 15.3 - 50)\hat i + 12.8 \hat j

d = 5.3\hat i + 12.8 \hat j

now total time duration of the motion is given as

T = 40 min + 20 min + 50 min

T = 1.83 h

now average velocity is given as

v_{avg} = \frac{5.3\hat i + 12.8\hat j}{1.83}

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Part a)

magnitude of the average velocity is given as

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{2.89^2 + 6.99^2}

v = 7.57 km/h

Part b)

Direction of the velocity is given as

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Answer:

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