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Vedmedyk [2.9K]
3 years ago
10

A 20-kg cart travels at 20 m/s in a circle with a radius of 20 m. What is the centripetal force?

Physics
2 answers:
tia_tia [17]3 years ago
8 0

Answer:

The equation for centripetal force is:

T = (mv^2)/r

T = centripetal force

m = mass

v = speed

r = radius

T = [20kg * (20 m/s * 20m/s)] / 20 m

T = [20kg * 400 m/s^2] / 20 m

T = 8,000 kg m/s^2 / 20 m

T = 400 N

Explanation:

Vlad1618 [11]3 years ago
5 0

Centripetal force = (mass) x (speed)² / (radius)

                           = (20 kg) x (20 m/s)² / (20 m)

                           = (20 x 20 / 20)  (kg-meter/sec²)

                           = 20 newtons


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Answer:

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Explanation:

Hi there!

The equations of height and velocity of the ball are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height at time t.

y0 = initial height.

v0 = initial velocity.

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Placing the origin at the throwing point, y0 = 0.

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Have a nice day!

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Answer:

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