Answer:
Explanation:
a)
d = separation of the slits = 0.30 mm = 0.30 x 10⁻³ m
λ = wavelength of the light = 496 nm = 496 x 10⁻⁹ m
n = order of the bright fringe
D = screen distance = 130 cm = 1.30 m
= Position of nth bright fringe
Position of nth bright fringe is given as
![x_{n} =\frac{ n D \lambda }{d}](https://tex.z-dn.net/?f=x_%7Bn%7D%20%3D%5Cfrac%7B%20n%20D%20%5Clambda%20%7D%7Bd%7D)
For n = 1
![x_{1} =\frac{ (1) (1.30)(496\times 10^{-9})}{0.30\times 10^{-3}}](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%5Cfrac%7B%20%281%29%20%281.30%29%28496%5Ctimes%2010%5E%7B-9%7D%29%7D%7B0.30%5Ctimes%2010%5E%7B-3%7D%7D)
![x_{1} = 2.15\times 10^{-3}m](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%202.15%5Ctimes%2010%5E%7B-3%7Dm)
For n = 2
![x_{2} =\frac{ (2) (1.30)(496\times 10^{-9})}{0.30\times 10^{-3}}](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%5Cfrac%7B%20%282%29%20%281.30%29%28496%5Ctimes%2010%5E%7B-9%7D%29%7D%7B0.30%5Ctimes%2010%5E%7B-3%7D%7D)
![x_{2} = 4.30\times 10^{-3}m](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%204.30%5Ctimes%2010%5E%7B-3%7Dm)
For n = 3
![x_{2} =\frac{ (2) (1.30)(496\times 10^{-9})}{0.30\times 10^{-3}}](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%5Cfrac%7B%20%282%29%20%281.30%29%28496%5Ctimes%2010%5E%7B-9%7D%29%7D%7B0.30%5Ctimes%2010%5E%7B-3%7D%7D)
![x_{2} = 6.45\times 10^{-3}m](https://tex.z-dn.net/?f=x_%7B2%7D%20%3D%206.45%5Ctimes%2010%5E%7B-3%7Dm)
b)
Position of nth dark fringe is given as
![y_{n} =\frac{ (2n+1) D \lambda }{2d}](https://tex.z-dn.net/?f=y_%7Bn%7D%20%3D%5Cfrac%7B%20%282n%2B1%29%20D%20%5Clambda%20%7D%7B2d%7D)
For n = 1
![y_{1} =\frac{ (2(1)+1) (1.30)(496\times 10^{-9})}{2(0.30\times 10^{-3})}](https://tex.z-dn.net/?f=y_%7B1%7D%20%3D%5Cfrac%7B%20%282%281%29%2B1%29%20%281.30%29%28496%5Ctimes%2010%5E%7B-9%7D%29%7D%7B2%280.30%5Ctimes%2010%5E%7B-3%7D%29%7D)
![y_{1} = 3.22\times 10^{-3}m](https://tex.z-dn.net/?f=y_%7B1%7D%20%3D%203.22%5Ctimes%2010%5E%7B-3%7Dm)
For n = 2
![y_{2} =\frac{ (2(2)+1) (1.30)(496\times 10^{-9})}{2(0.30\times 10^{-3})}](https://tex.z-dn.net/?f=y_%7B2%7D%20%3D%5Cfrac%7B%20%282%282%29%2B1%29%20%281.30%29%28496%5Ctimes%2010%5E%7B-9%7D%29%7D%7B2%280.30%5Ctimes%2010%5E%7B-3%7D%29%7D)
![y_{2} = 5.4\times 10^{-3}m](https://tex.z-dn.net/?f=y_%7B2%7D%20%3D%205.4%5Ctimes%2010%5E%7B-3%7Dm)
For n = 3
![y_{3} =\frac{ (2(3)+1) (1.30)(496\times 10^{-9})}{2(0.30\times 10^{-3})}](https://tex.z-dn.net/?f=y_%7B3%7D%20%3D%5Cfrac%7B%20%282%283%29%2B1%29%20%281.30%29%28496%5Ctimes%2010%5E%7B-9%7D%29%7D%7B2%280.30%5Ctimes%2010%5E%7B-3%7D%29%7D)
![x_{3} = 7.5\times 10^{-3}m](https://tex.z-dn.net/?f=x_%7B3%7D%20%3D%207.5%5Ctimes%2010%5E%7B-3%7Dm)
Hello.
The answer is: D. weak nuclear force.
The weak force causes beta decay, a form of radioactivity. It could not be explained by the strong nuclear force, the force that’s responsible for holding the atomic nucleus together, because this force doesn’t affect electrons.
It couldn’t be the electromagnetic force, because this does not affect neutrons, and the force of gravity is far too weak to be responsible.
Have a nice day
Answer:
45000cm2(cuarenta y cinco mil centimetros al cuadrado).
Explanation:
porque el volumes es igual a el área de la base por la altra