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larisa [96]
2 years ago
15

You do an experiment in which you need 0.5 moles of tyrosine (C9H11NO3). How many grams must you weigh out?

Chemistry
1 answer:
Yuki888 [10]2 years ago
5 0

Answer: a)  90.5g

b) 33.6 L

Explanation:-

Molar mass of tyrosine  (C_9H_{11}NO_3)= 181 g/mol

According to Avogadro's law, 1 mole of every substance weighs equal to its molar mass.

1 mole of tyrosine  (C_9H_{11}NO_3) weighs = 181 g/mol

0.5 moles of tyrosine  (C_9H_{11}NO_3) weigh =\frac{181g/mol}{1}\times 0.5moles=90.5g

b) According to Avogadro's law, 1 mole of an ideal gas occupies 22.4 Liters at Standard conditions of temperature and pressure (STP).

1 mole of gas at STP occupy = 22.4 L

1.5 moles of gas at STP occupy =\frac{22.4L}{1}\times 1.5=33.6L



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