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aleksandr82 [10.1K]
3 years ago
13

What does the electron transport chain do to the concentration of hydrogen ions (protons)?

Chemistry
1 answer:
choli [55]3 years ago
3 0
It makes the concentration of protons higher outside of the membrane than the inside

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What is true of a basic solution at room temperature? it has a ph value below 7. it has a greater concentration of hydroxide com
slega [8]
The true statement about basic solution at room temperature is that it has a greater concentration of hydroxide compared to hydronium ions.
Basic solutions have always pH greater than 7.
Basic solutions have bitter and caustic taste.
Basic solutions are not used as conductors in car batteries, acidic electrolytes are used in car batteries.
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3 years ago
How many “dots” would be around the central atom in the Lewis structure of S?
agasfer [191]
B) 6
one above one below and 2 on the left and right sides
6 0
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How many moles are in a 111.5 gram sample of sodium chloride, NaCl?
Katarina [22]

Answer: 1.91 moles

Explanation:

First you want to find the molar mass of NaCL

Na = 22.99g  Cl = 35.45g

22.99g + 35.45g = 54.44g

Then divide 111.5g by 54.44g and this will give you moles.

5 0
2 years ago
Please help me, I am confused on this.
weeeeeb [17]

Answer:

The First choice is correct

Explanation:

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4 0
3 years ago
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Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio
umka21 [38]

Answer : The value of K_p at this temperature is 66.7

Explanation : Given,

Pressure of PCl_3 at equilibrium = 0.348 atm

Pressure of Cl_2 at equilibrium = 0.441 atm

Pressure of PCl_5 at equilibrium = 10.24 atm

The balanced equilibrium reaction is,

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}

Now put all the values in this expression, we get :

K_p=\frac{(10.24)}{(0.348)(0.441)}

K_p=66.7

Therefore, the value of K_p at this temperature is 66.7

4 0
2 years ago
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