Answer:
mass (g) needed = 710.2 grams Na₂SO₄(s)
Explanation:
Needed is 2.5 Liters of 2.0M Na₂SO₄; formula wt Na₂SO₄ = 142.04g/mol.
mass (grams) of Na₂SO₄(s) = Molarity needed x Volume needed in Liters x Formula Wt of solute
mass (grams) of Na₂SO₄(s) = (2.5L)(2.0M)(142.04g/mol) = 710.2 grams Na₂SO₄(s)
Mixing: Transfer 710.4 grams Na₂SO₄ into mixing vessel and add water-solvent up to but not to exceed 2.5 Liters total volume. Mix until dissolved.
Gives 2.5 Liters of 2.0M Na₂SO₄(aq) solution.
Answer:
a
Explanation:
because titration by definition, is used to determine the concentration of one reactant in an aqueous solution, it requires a burette to accurately measure the volume of a solution and endpoints in acid-base titration can be determined by a colour indicator or a pH meter
Answer:
1.7 M
Explanation:
Concentration is the number of moles of solute dissolved in 1 L of solution
Concentration = number of moles of solute / volume of solution
Number of moles of solute needs to be calculated first
Mass of methanol - 12.5 g
Molar mass of methanol - 32 g/mol
Number of methanol moles - 12.5 g / 32 g/mol = 0.39 mol
Therefore concentration is = 0.39 mol / 0.230 L = 1.7 mol/L
Concentration is 1.7 M
<h2>
Answer:It always contains certain elements,It always contains elements in definite proportions.,It cannot contain atoms from more than one element.</h2>
Explanation:
The mineral need not occur always in a pure form.On purification we get the exact chemical composition.
The mineral always has a definite chemical composition which means the number of elements and types of elements in the mineral does not change.
Since the mineral has definite composition,the elements in the mineral has definite proportions.
The mineral can be a compound.So,there can be atoms from more than one element.
Answer:
9.62moles of NH₃
Explanation:
Given parameters:
Number of moles of nitrogen = 4.81moles
Unknown:
Number of moles of NH₃ = ?
Solution:
To solve this problem, we need to establish a balanced reaction equation:
N₂ + 3H₂ → 2NH₃
Now, we can solve the problem by working from the known to the unknown.
1 mole of N₂ produced 2 moles of NH₃
4.81moles of N₂ will produce 2 x 4.81 = 9.62moles of NH₃