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Kisachek [45]
3 years ago
11

What is the ground state electron configuration for Ru2+?

Chemistry
2 answers:
Natali5045456 [20]3 years ago
5 0

Electronic configuration: The distribution or arrangement of electrons of a molecule or an atom in molecular or atomic orbitals.

Ground state electron configuration: The distribution of electrons of an atom or molecule around the nucleus with lower levels of energy.

Now, Ru stands for Ruthenium with atomic number 44. It is a metal and thus, has ability to lose electrons and, becomes positively charged ion.

One can write the electronic configuration with the help of atomic number and Afbau principle, Pauli exclusion principle etc.

Ground electronic Configuration is as follows:

Ru = s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{1}4d^{7}

Soft Hand notation: [Kr]4d^{7}5s^{1}

Now, when ruthenium loses two electrons then it becomes Ru^{+2}, thus electron configuration becomes

Soft Hand notation: [Kr]4d^{6}

The ground state electronic configuration of Ruthenium is [Kr]4d^{7}5s^{1} and when it loses two electrons, then electronic configuration becomes [Kr]4d^{6} ( Ru^{+2})





goblinko [34]3 years ago
4 0
The correct answer to this question is "[Kr]4d^6." 

the ground state electron configuration for Ru2+ is <span>"[Kr]4d^6." 
</span>
As you know, the ground state electron configuration for <span>R<span>u2+</span></span> is Ru. However, Ru is a special case; its electron configuration is <span>[Kr]4d75s1</span>.
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During photosynthesis, what gas do plants release - oxygen
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2 years ago
My professor gave me two questions to solve using the Van Der Waals Equation. She told us to solve for P and the second one we h
Fed [463]

Answer:

P=atm

b=\frac{L}{mol}

Explanation:

The problem give you the Van Der Waals equation:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

First we are going to solve for P:

(P+\frac{n^{2}a}{V^{2}})=\frac{nRT}{(V-nb)}

P=\frac{nRT}{(V-nb)}-\frac{n^{2}a}{v^{2}}

Then you should know all the units of each term of the equation, that is:

P=atm

n=mol

R=\frac{L.atm}{mol.K}

a=atm\frac{L^{2}}{mol^{2}}

b=\frac{L}{mol}

T=K

V=L

where atm=atmosphere, L=litters, K=kelvin

Now, you should replace the units in the equation for each value:

P=\frac{(mol)(\frac{L.atm}{mol.K})(K)}{L-(mol)(\frac{L}{mol})}-\frac{(mol^{2})(\frac{atm.L^{2}}{mol^{2}})}{L^{2}}

Then you should multiply and eliminate the same units which they are dividing each other (Please see the photo below), so you have:

P=\frac{L.atm}{L-L}-atm

Then operate the fraction subtraction:

P=P=\frac{L.atm-L.atm}{L}

P=\frac{L.atm}{L}

And finally you can find the answer:

P=atm

Now solving for b:

(P+\frac{n^{2}a}{V^{2}})(V-nb)=nRT

(V-nb)=\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

nb=V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}

b=\frac{V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}}{n}

Replacing units:

b=\frac{L-\frac{(mol).(\frac{L.atm}{mol.K}).K}{(atm+\frac{mol^{2}.\frac{atm.L^{2}}{mol^{2}}}{L^{2}})}}{mol}

Multiplying and dividing units,(please see the second photo below), we have:

b=\frac{L-\frac{L.atm}{atm}}{mol}

b=\frac{L-L}{mol}

b=\frac{L}{mol}

7 0
3 years ago
Which of the following coefficients are needed to balance the combustion reaction of ethanol?
djyliett [7]
Answer is: d. 3,2,3.

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H₂O is water.
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5 0
3 years ago
Determine the volume in liters occupied by 22.6 g of I2 gas at STP.
AleksandrR [38]

 The volume in liters  occupied  by 22.6 g  of I₂  gas  at STP  is  1.99 L (answer A)

 <u><em>calculation</em></u>

Step: find the  moles of I₂

moles= mass÷  molar mass

from  periodic table the  molar mass  of I₂  is  253.8 g/mol

moles = 22.6 g÷253.8 g/mol =0.089 moles

Step 2:find the volume  of I₂  at STP

At STP  1  moles =22.4 L

         0.089 moles= ? L

<em>by cross  multiplication</em>

={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L


6 0
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The high electrical conductivity of metals is primarily due to
zubka84 [21]

High conductivity of metals is caused by electrons that are free to move through the lattice.

hope this helps!

7 0
2 years ago
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