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3 years ago

7

A string of mass 60.0 g and length 2.0 m is fixed at both ends and with 500 N in tension. a. If a wave is sent along this string

, what will be the wave's speed? A second wave is sent in the string, what is the new speed of each of the two waves?

1 answer:

Darya [45]3 years ago

8 0

Answer:

a

The speed of wave is $v_1 = 129.1 \ m/s$

b

The new speed of the two waves is $v = 129.1 \ m/s$

Explanation:

From the question we are told that

The mass of the string is $m = 60 \ g = 60 *10^{-3} \ kg$

The length is $l = 2.0 \ m$

The tension is $T = 500 \ N$

Now the velocity of the first wave is mathematically represented as

$v_1 = \sqrt{ \frac{T}{\mu} }$

Where $\mu$ is the linear density which is mathematically represented as

$\mu = \frac{m}{l}$

substituting values

$\mu = \frac{ 60 *10^{-3}}{2.0 }$

$\mu = 0.03\ kg/m$

So

$v_1 = \sqrt{ \frac{500}{0.03} }$

$v_1 = 129.1 \ m/s$

Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )

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2 years ago

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3 years ago

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Answer:

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According to Archimedes' principle, the thrust received by an object immersed a fluid is equal to the weight of the fluid displaced;

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The mass of the water displaced by the boat = (Density of seawater) × (Volume of seawater displaced)

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Where;

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The up-thrust on the boat = The weight of the seawater displaced

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