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Nostrana [21]
3 years ago
11

Physical science semester B exam 66 problems , please don’t delete I’m on my last leg I need this please god help me

Physics
1 answer:
krek1111 [17]3 years ago
7 0
HI!! If you need answers to your exam, then go to https://quizlet.com/ then search for what you need!! I hope this helps I am not sure what your exam is for, and I don't have enough info to tell you all the answers, but hopefully, this will help you!!

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Please help!!!! Will mark brainliest.
julia-pushkina [17]

Answer:

Approximately 8.4 \times 10^{2}\; \rm N, assuming that g = 9.8\; \rm m \cdot s^{-2}.

Explanation:

Let m and a denote the mass and acceleration of Spiderman, respectively.

There are two forces on Spiderman:

  • Downward gravitational attraction from the earth: W = m \cdot g.
  • Upward tension force from the strand of web F(\text{tension}).

The directions of these two forces are exactly opposite of one another. Besides, because Spiderman is accelerating upwards, the magnitude of F(\text{tension}) (which points upwards) should be greater than that of W (which points downwards towards the ground.)

Subtract the smaller force from the larger one to find the net force on Spiderman:

(\text{Net Force}) = F(\text{tension}) - W.

On the other hand, apply Newton's Second Law of motion to find the value of the net force on Spiderman:

(\text{Net Force}) = m \cdot a.

Combine these two equations to get:

m \cdot a = (\text{Net Force}) = F(\text{tension}) - W.

Therefore:

\begin{aligned}& F(\text{tension})\\ &= m \cdot a + W \\ &= m \cdot (a + g)\\ &= 76\; \rm kg \times \left(1.3\; \rm m \cdot s^{-2} + 9.8\; \rm m \cdot s^{-2}\right)\\ &\approx 8.4\times 10^{2}\; \rm N\end{aligned}.

By Newton's Third Law of motion, Spiderman would exert a force of the same size on the strand of web. Hence, the size of the force in the strand of the web should be approximately 8.4\times 10^{2}\; \rm N (downwards.)

4 0
3 years ago
A differnece in electric potential is required for an electric charge to flow through a wire.
cupoosta [38]

Answer:

TRUE

Explanation:

6 0
2 years ago
Read 2 more answers
Which is a legacy of the enlightenment?
stealth61 [152]
Education that result in understanding and the spread knowledge physics
7 0
3 years ago
Read 2 more answers
6000 kg train moving 5 m/sec to east collides with 5000 kg train moving 3 m/sec to west. What is their velocity
Svetlanka [38]

The final velocity is 1.37 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.

So we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v

where:

m_1 = 6000 kg is the mass of the first train

u_1 = 5 m/s is the initial velocity of the first train (we take east as positive direction)

m_2 = 5000 kg is the mass of the second train

u_2 = -3 m/s is the initial velocity of the second train

v is the final combined velocity of the two trains

Re-arranging the equation and substituting the values, we find:

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(6000)(5)+(5000)(-3)}{6000+5000}=1.37 m/s

And the positive sign indicates their final direction is east.

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

8 0
3 years ago
The refractive index of glass is 1.52
Ksenya-84 [330]

Explanation:

..upper side is glass ..

3 0
3 years ago
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