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tia_tia [17]
3 years ago
12

The siren of a police car at rest emits at a predominant frequency of 1980 Hz. What frequency will you hear if you are at rest a

nd the police car moves at 34.3.0m/s (a) toward you, and (b) away from you? Please Explain
Physics
1 answer:
Naddika [18.5K]3 years ago
6 0

Answer:

(a) 1782 Hz (b) 2178 Hz

Explanation:

The predominant frequency =1980 Hz

The speed of the police car =34.3 m/sec

The speed of sound in air =343 m/sec

(a) When the car moves towards you

According to Doppler's effect

f=f_0\frac{v-v_s}{v}=1980\times \frac{343-34.3}{343}=1782Hz

(b) When the car moves away from you

f=f_0\frac{v+v_s}{v}=1980\times \frac{343+34.3}{343}=2178Hz

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Lemur [1.5K]

In simple words, flux can be stated as the rate of flow of a fluid, radiant energy, or particles across a given area.

<u>Explanation:</u>

<u>Mutual Flux:</u>

  • The magnetic lines present in among two magnets or solenoid is mutual flux.
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  • The SI unit of mutual flux is the Henry

<u>Leakage Flux:</u>

  • In simple words, it can be stated as  the magnetic flux which does not follow the specially designed way in a magnetic circuit.
  • Leakage flux in the induction motor takes spot due to current runs through the essence of the induction motor.
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<u>Magnetizing flux</u>

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3 0
3 years ago
A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of
Leto [7]

Answer: 2.27\ m/s^2

Explanation:

Given

Length of the race track L=200\ m

the radius of curvature of the track r=29.5\ m

time taken to run on track is t=24.4\ s

Speed of runner is

\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s

Centripetal acceleration is

\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2

5 0
3 years ago
An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric
8090 [49]

Answer:

1.) 11 km/s

2.) 9.03 × 10^-5 metres

Explanation:

Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

Electron q = 1.6×10^-19 C

Electron mass = 9.11×10^-31 Kg

(a) What is the speed of the electron 1.3 ns after entering this region?

E = F/q

F = Eq

Ma = Eq

M × V/t = Eq

Substitute all the parameters into the formula

9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

V = 7.68×10^-18 /7.0×10^-22

V = 10971.43 m/s

V = 11 Km/s approximately

(b) How far does the electron travel during the 1.3 ns interval?

The initial velocity U = 64 km/s

S = ut + 1/2at^2

S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

S =8.32×10^-5 + 7.13×10^-6

S = 9.03 × 10^-5 metres

3 0
3 years ago
Hello! I am taking physics H on edge 2021 and if someone could give me the completed Electromagnetic Fields Plan an Investigatio
kumpel [21]

Answer:

AA

Explanation:

AA

7 0
2 years ago
Cosmologists study ______.
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Your answer is:

<em>The origin, structure, and future of the universe</em>

You can just search up the definition of Cosmology and receive your answer. Hopefully this helps at least a little :3

6 0
3 years ago
Read 2 more answers
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