Which would have the longer orbital period: a moon 1 million km from the center of Jupiter, or a moon 1 million km from the cent
1 answer:
Answer:
earth
Explanation:
The formula for the orbital period of the moon is given by
As the time period is inversely proportional to the square root of the acceleration due to gravity of the planet.
As the value of acceleration due to gravity on Jupiter is more than the earth, so the period of moon around the earth is large as compared to the period of the moon around the Jupiter when the distance is same.
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Ans: R = Ball Travelled = 92.15 meters.
Explanation:
First we need to derive that formula for the "range" in order to know how far the ball traveled before hitting the ground.
Along x-axis, equation would be:
Since there is no acceleration along x-direction; therefore,
Since
and 
=0; therefore above equation becomes,
--- (A)
Now we need to find "t", and the time is not given. In order to do so, we shall use the y-direction motion equation. Before hitting the ground y ≈ 0 and a = -g; therefore,
=>
=>
Since
; therefore above equation becomes,
Put the value of t in equation (A):
(A) =>
Where x = Range = R, and
; therefore above equation becomes:
=>
Now, as:
and
°
and g = 9.8 m/(s^2)
Hence,
Ans: R = 92.15 meters.
-i
Explanation:
First we need to derive that formula for the "range" in order to know how far the ball traveled before hitting the ground.
Along x-axis, equation would be:
Since there is no acceleration along x-direction; therefore,
Since
Now we need to find "t", and the time is not given. In order to do so, we shall use the y-direction motion equation. Before hitting the ground y ≈ 0 and a = -g; therefore,
=>
=>
Since
Put the value of t in equation (A):
(A) =>
Where x = Range = R, and
=>
Now, as:
and
and g = 9.8 m/(s^2)
Hence,
Ans: R = 92.15 meters.
-i