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Vika [28.1K]
3 years ago
7

Someone pls help I don’t understand this

Physics
1 answer:
ozzi3 years ago
3 0

Answer:

{ \rm{F _{ball \: on \: bat} =  - F _{bat \: on \: ball}  }}

Explanation:

• This is due to the third newtons law of motion which states that "<em>E</em><em>v</em><em>e</em><em>r</em><em>y</em><em> </em><em>a</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>h</em><em>a</em><em>s</em><em> </em><em>a</em><em>n</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>l</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>o</em><em>p</em><em>p</em><em>o</em><em>s</em><em>i</em><em>t</em><em>e</em><em> </em><em>reaction</em>".

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A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on
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Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

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Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

Ec=\frac{1}{2} *m*v^{2}

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The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}

W=\frac{1}{2} *m*(v2^{2}-v1^{2})

In this case:

  • W=?
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Replacing:

W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})

W= -515,872.5 J

<u><em>The work required is -515,872.5 J</em></u>

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