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Rudik [331]
3 years ago
10

QUICK HURRY FIRST ANSWER GETS BRAINLIST!!!! Why is it important to add coefficients to the

Chemistry
1 answer:
kirill115 [55]3 years ago
5 0
The coefficients in a balanced chemical equation are important because they give the ratio of the reactants and the products. Those ratios are fixed and when the reagents react do it in the same proportion and yield the products in the same proportion of the coefficients. Then, the coefficients are the basis for the calculations of the amount of substances that react and the amount of substances that are formed as result of the reaction.
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How many moles are present in 60 grams of hydrochloric acid, HClHClH?
Brilliant_brown [7]

Answer:

C 60

Explanation:

5 0
3 years ago
Type of reaction based on the reactants<br> FeCl3 +K →
strojnjashka [21]

Answer:

complexation

Explanation:

KSCN + FeCl 3 → K + + [FeSCN] 2+ + 3 Cl. This is a complexation reaction: [FeSCN] 2+ is the formed complex.

3 0
3 years ago
Is a Mercury Thermometer a pure substance or a mixture?
alisha [4.7K]
The mercury inside the thermometer is a pure substance hope this helps :)
5 0
3 years ago
Select the correct statement about isotopes. A. All the isotopes of an element are radioactive. B. Isotopes of the same element
frutty [35]

Answer: Option (B) is the correct answer.

Explanation:

Isotopes are the substances or species that contain same number of protons but different number of neutrons.

As it is known that atomic number means the total number of protons present in an atom. Hence, this also means that in isotopes atomic number of the species is same.

For example, isotopes of hydrogen are ^{1}_{1}H, ^{2}_{1}H, and ^{3}_{1}H.

Isotopes of only heavier elements are radioactive in nature as they have large difference in the number of protons and neutrons.

Thus, we can conclude that the statement isotopes of the same element have the same atomic number but differ in their atomic masses, is correct.

7 0
3 years ago
What hybridization is required for central atoms that have a tetrahedral arrangement of electron pairs? A trigonal planar arrang
Ksivusya [100]

Answer:

The required hybridization for a central atom that have:

a tetrahedral arrangement of electron pairs        is  sp^3

a trigonal planar arrangement of electron pairs   is  sp^2

a linear arrangement of electron pairs                 is   sp

Explanation:

From the given information:

The required hybridization for a central atom that have:

a tetrahedral arrangement of electron pairs        is  sp^3

a trigonal planar arrangement of electron pairs   is  sp^2

a linear arrangement of electron pairs                 is   sp

Hybridization is the mixing and blending of two or more pure atomic orbitals ( s, p and d) to forma two or more hybrid atomic orbitals that are identical in shape and energy e. sp ,sp² , sp³, sp³d hybrid orbitals.

Examples:

Tetrahedral

In CH₄ , carbon C is the central atom.

A 2s electron is excited from the ground state of boron 1s²2s²2p² to one of the empty orbitals to 2p to give the excited state 1s²2s²2p³.

In the excited state of carbon, the 2-s orbital can be mixed with the 2p orbitals in three ways : sp³, sp² and sp hybridization. For the formation of four sp³ hybrid orbitals, the 2s orbital are mixed with all the three p orbitals. The four sp³ hybrid orbitals are tetrahedrally arranged with a bond angle of 109.5⁰

Trigonal Planar

In BF₃ , Boron B is the central atom

A 2s electron is excited from the ground state of boron 1s²2s²2p¹ to one of the empty orbitals to 2p. The 2s orbital is then mixed with two orbitals of 2p to form three sp² hybrid orbitals that are trigonal planar arranged in the plane in order to minimize repulsion. They bonds between them form an equal strength and with bond angles of 120⁰

Linear arrangement:

In BeCl₂, Be is the central atom

To provide the unpaired electrons for covalent bonds a 2s electron is excited to a 2p orbital. Thereafter, the two atomic orbitals hybridize to give two identical orbitals called sp hybrid orbitals. The  sigma bond for,ed are equal in bond lengths and form a bond angle of 180°

3 0
3 years ago
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