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Andrej [43]
2 years ago
9

A raft has a mass of 152 kg. When a

Physics
2 answers:
True [87]2 years ago
6 0

Answer:

72

Explanation:

trapecia [35]2 years ago
3 0

Answer:

72 kg

Explanation:

The computation of the mass of the person is shown below:

As we know that

Water displaced weight = Raft weight + person weight

P_w.V = M_r + M_p

where

P_w denotes the water density i.e. 1000 kg/m^3

V denotes the volume of the water in m^3

Now

1000 × 0.224 = 152 + M_p

M_p = 224 - 152

= 72 kg

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A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying p
Semenov [28]

Answer:

f_n=3.75N

Explanation:

From the question we are told that:

Frictional force F=0.150N

Coefficient of kinetic friction \mu=0.04

Generally the equation for Normal for is mathematically given by

 f_n=\frac{F}{\mu}

Therefore

 f_n=\frac{0.150}{0.04}

 f_n=3.75N

5 0
2 years ago
Carol drops a stone in a mine shaft 122.5 metres deep.How
Verizon [17]

Answer:

 T = 5.36 s

Explanation:

given,

depth of the mine shaft = 122.5 m

speed of the sound = 340 m/s

time taken  = ?

time taken by the stone to reach at the bottom

using equation of motion

s = u t + \dfrac{1}{2}gt^2

initial speed , u = 0 m/s

t = \sqrt{\dfrac{2s}{g}}

t = \sqrt{\dfrac{2\times 122.5}{9.8}}

       t = 5 s

time taken by the sound to travel

    d =v x t

 t = \dfrac{d}{v}

 t = \dfrac{122.5}{340}

    t = 0.36 s

total time taken for the sound to reach carol after dropping the stone

T = 5 + 0.36

 T = 5.36 s

7 0
3 years ago
A father places his daughter in a swing that is 0.60\,\text{m}0.60m0, point, 60, start text, m, end text above ground. Then he r
schepotkina [342]

This question involves the concepts of the law of conservation of energy and kinetic energy.

The girl's fastest speed is "3.7 m/s".

According to the law of conservation of energy, the girl will have the fastest speed at mean position, which will be calculated as follows:

Loss in Potential Energy = Gain in Kinetic Energy

mg\Delta h=\frac{1}{2}mv^2\\\\v=\sqrt{2g\Delta h}

where,

v = maximum speed = ?

g = acceleration due to gravity = 9.81 m/s²

Δh = change in height = 1.3 m - 0.6 m = 0.7 m

Therefore,

v=\sqrt{2(9.81\ m/s^2)(0.7\ m)}

<u>v = 3.7 m/s</u>

<u></u>

Learn more about the Law of Conservation of Energy here:

brainly.com/question/381281?referrer=searchResults

5 0
2 years ago
Yung's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a sc
Lady bird [3.3K]

Answer:

1.082 mm

Explanation:

From the question, we can see that we were given The following

Wavelength of the atoms, λ = 502 nm = 502*10^-9 m

Radius of the screen away from the double slit, r = 1.1 m

We know that Y(20) = 10.2 mm = 10.2*10^-3 m

d = (20 * R * λ) / Y(20)

d = (20 * 1.1 * 502*10^-9)/10.2*10^-3

d = 1.1*10^-5 / 10.2*10^-3

d = 1.082 mm

Therefore, we can say that the distance of separation between the two slits is 1.082 mm

4 0
3 years ago
A plane cruising at 233 m/s accelerates at 17 m/s 2 for 4.8 s. What is its final velocity? Answer in units of m/s. 013 (part 2 o
Volgvan

Answer:

Final velocity will be 314.6 m/sec

Distance traveled = 1314.24 m

Explanation:

We have given initial velocity u = 233 m/sec

Acceleration a=17m/sec^2

Time t = 4.8 sec

From first equation of motion v=u+at, here v is final velocity, u is initial velocity and t is time

So v=233+17\times 4.8=314.6m/sec

Now we have to find distance traveled

From second equation of motion

S=ut+\frac{1}{2}at^2=233\times 4.8+\frac{1}{2}\times 17\times 4.8^2=1314.24m

So distance traveled in given time will be 1314.24 m

4 0
3 years ago
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