Answer:
![V = IR](https://tex.z-dn.net/?f=V%20%3D%20IR)
Explanation:
Required
Which equation represents ohm's law?
Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).
Mathematically, this can be represented as:
![I\ \alpha\ \frac{V}{R}](https://tex.z-dn.net/?f=I%5C%20%5Calpha%5C%20%5Cfrac%7BV%7D%7BR%7D)
Convert the expression to an equation
![I\ =\ \frac{V}{R}](https://tex.z-dn.net/?f=I%5C%20%3D%5C%20%5Cfrac%7BV%7D%7BR%7D)
Multiply both sides by R to make V the subject
![I\ * R\ =\ \frac{V}{R} * R](https://tex.z-dn.net/?f=I%5C%20%2A%20R%5C%20%3D%5C%20%5Cfrac%7BV%7D%7BR%7D%20%2A%20R)
![I\ * R\ =V](https://tex.z-dn.net/?f=I%5C%20%2A%20R%5C%20%3DV)
Reorder
![V = I\ * R](https://tex.z-dn.net/?f=V%20%3D%20I%5C%20%2A%20R)
![V = IR](https://tex.z-dn.net/?f=V%20%3D%20IR)
<em>Option (a) is correct; Others are not</em>
Answer:
p = 1.16 10⁻¹⁴ C m and ΔU = 2.7 10 -11 J
Explanation:
The dipole moment of a dipole is the product of charges by distance
p = 2 a q
With 2a the distance between the charges and the magnitude of the charges
p = 1.7 10⁻⁹ 6.8 10⁻⁶
p = 1.16 10⁻¹⁴ C m
The potential energie dipole is described by the expression
U = - p E cos θ
Where θ is the angle between the dipole and the electric field, the zero value of the potential energy is located for when the dipole is perpendicular to the electric field line
Orientation parallel to the field
θ = 0º
U = 1.16 10⁻¹⁴ 1160 cos 0
U1 = 1.35 10⁻¹¹ J
Antiparallel orientation
θ = 180º
cos 180 = -1
U2 = -1.35 10⁻¹¹ J
The difference in energy between these two configurations is the subtraction of the energies
ΔU = | U1 -U2 |
ΔU = 1.35 10-11 - (-1.35 10-11)
ΔU = 2.7 10 -11 J
Answer
• Improving the environmental performances
• Developing Green Mining technology
Explanation
The effect to the environment caused by opal mining are; impact on soils and geology, clearing of native vegetation disrupting flora and fauna, change in land use and effects of air quality.
Opal mining is currently examining environmental impacts and adopting measures that mitigate the impacts making the process less destructive to the environment.
With the current commitment to sustainability, opal companies are investing funds for Green Mining as a positive way to impact the environment before and after mining.
Answer
given,
mass of satellite = 545 Kg
R = 6.4 x 10⁶ m
H = 2 x 6.4 x 10⁶ m
Mass of earth = 5.972 x 10²⁴ Kg
height above earth is equal to earth's mean radius
a) satellite's orbital velocity
centripetal force acting on satellite = ![\dfrac{mv^2}{r}](https://tex.z-dn.net/?f=%5Cdfrac%7Bmv%5E2%7D%7Br%7D)
gravitational force = ![\dfrac{GMm}{r^2}](https://tex.z-dn.net/?f=%5Cdfrac%7BGMm%7D%7Br%5E2%7D)
equating both the above equation
![\dfrac{mv^2}{r} = \dfrac{GMm}{r^2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bmv%5E2%7D%7Br%7D%20%3D%20%5Cdfrac%7BGMm%7D%7Br%5E2%7D)
![v = \sqrt{\dfrac{GM}{r}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cdfrac%7BGM%7D%7Br%7D%7D)
![v = \sqrt{\dfrac{6.67 \times 10^{-11}\times 5.972 \times 10^{24}}{2 \times 6.4 \times 10^6}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cdfrac%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%5Ctimes%205.972%20%5Ctimes%2010%5E%7B24%7D%7D%7B2%20%5Ctimes%206.4%20%5Ctimes%2010%5E6%7D%7D)
v = 5578.5 m/s
b) ![T= \dfrac{2\pi\ r}{v}](https://tex.z-dn.net/?f=T%3D%20%5Cdfrac%7B2%5Cpi%5C%20r%7D%7Bv%7D)
![T= \dfrac{2\pi\times 2\times 6.4 \times 10^6}{5578.5}](https://tex.z-dn.net/?f=T%3D%20%5Cdfrac%7B2%5Cpi%5Ctimes%202%5Ctimes%206.4%20%5Ctimes%2010%5E6%7D%7B5578.5%7D)
![T= \dfrac{2\pi\times 2\times 6.4 \times 10^6}{5578.5}](https://tex.z-dn.net/?f=T%3D%20%5Cdfrac%7B2%5Cpi%5Ctimes%202%5Ctimes%206.4%20%5Ctimes%2010%5E6%7D%7B5578.5%7D)
T = 14416.92 s
![T = \dfrac{14416.92}{3600}\ hr](https://tex.z-dn.net/?f=T%20%3D%20%5Cdfrac%7B14416.92%7D%7B3600%7D%5C%20hr)
T = 4 hr
c) gravitational force acting
![F = \dfrac{GMm}{r^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7BGMm%7D%7Br%5E2%7D)
![F = \dfrac{6.67 \times 10^{-11}\times 545 \times 5.972 \times 10^{24} }{(6.46 \times 10^6)^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Cdfrac%7B6.67%20%5Ctimes%2010%5E%7B-11%7D%5Ctimes%20545%20%5Ctimes%205.972%20%5Ctimes%2010%5E%7B24%7D%20%7D%7B%286.46%20%5Ctimes%2010%5E6%29%5E2%7D)
F = 5202 N