<h3>
Answer:</h3>
172.92 °C
<h3>
Explanation:</h3>
Concept being tested: Quantity of heat
We are given;
- Specific heat capacity of copper as 0.09 cal/g°C
- Quantity of heat is 8373 calories
- Mass of copper sample as 538.0 g
We are required to calculate the change in temperature.
- In this case we need to know that the amount of heat absorbed or gained by a substance is given by the product of mass, specific heat capacity and change in temperature.
Therefore, to calculate the change in temperature, ΔT we rearrange the formula;
ΔT = Q ÷ mc
Thus;
ΔT = 8373 cal ÷ (538 g × 0.09 cal/g°C)
= 172.92 °C
Therefore, the change in temperature will be 172.92 °C
Answer:
c. find the slope of the velocity time graph
The answer to this question is:
D) Disorder
Answer:
a) a = 3.72 m / s², b) a = -18.75 m / s²
Explanation:
a) Let's use kinematics to find the acceleration before the collision
v = v₀ + at
as part of rest the v₀ = 0
a = v / t
Let's reduce the magnitudes to the SI system
v = 115 km / h (1000 m / 1km) (1h / 3600s)
v = 31.94 m / s
v₂ = 60 km / h = 16.66 m / s
l
et's calculate
a = 31.94 / 8.58
a = 3.72 m / s²
b) For the operational average during the collision let's use the relationship between momentum and momentum
I = Δp
F Δt = m v_f - m v₀
F =
F = m [16.66 - 31.94] / 0.815
F = m (-18.75)
Having the force let's use Newton's second law
F = m a
-18.75 m = m a
a = -18.75 m / s²