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Juliette [100K]
2 years ago
6

SOMEONE PLEASE HELP!!

Physics
1 answer:
Arisa [49]2 years ago
7 0

Hello!

\large\boxed{\text{C. 7,350,000 J}}

Use the equation:

PE = mgh

Where:

m = mass of the object (kg)

g = acceleration due to gravity (≈9.8 m/s)

h = height above ground (m)

Plug the given values into the equation:

PE = 7500 · 9.8 · 100

PE = 7,350,000 Joules.

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Copper has a specific heat of 0.09 cal/g x C . How much change in temperature would the addition of 8373 cal of heat have on a 5
neonofarm [45]
<h3>Answer:</h3>

172.92 °C

<h3>Explanation:</h3>

Concept being tested: Quantity of heat

We are given;

  • Specific heat capacity of copper as 0.09 cal/g°C
  • Quantity of heat is 8373 calories
  • Mass of copper sample as 538.0 g

We are required to calculate the change in temperature.

  • In this case we need to know that the amount of heat absorbed or gained by a substance is given by the product of mass, specific heat capacity and change in temperature.
  • That is, Q = m × c × ΔT

Therefore, to calculate the change in temperature, ΔT we rearrange the formula;

ΔT = Q ÷ mc

Thus;

ΔT = 8373 cal ÷ (538 g × 0.09 cal/g°C)

    = 172.92 °C

Therefore, the change in temperature will be 172.92 °C

3 0
3 years ago
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belka [17]
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How can you use graphs to calculate the displacement of an object?
tekilochka [14]

Answer:

c. find the slope of the velocity time graph

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2 years ago
1. Which word or phrase best describes entropy?
Mama L [17]
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An initially motionless test car is accelerated to 115 km/h in 8.58 s before striking a simulated deer. The car is in contact wi
hoa [83]

Answer:

a)       a = 3.72 m / s², b)    a = -18.75 m / s²

Explanation:

a) Let's use kinematics to find the acceleration before the collision

             v = v₀ + at

as part of rest the v₀ = 0

             a = v / t

Let's reduce the magnitudes to the SI system

              v = 115 km / h (1000 m / 1km) (1h / 3600s)

              v = 31.94 m / s

              v₂ = 60 km / h = 16.66 m / s

l

et's calculate

             a = 31.94 / 8.58

             a = 3.72 m / s²

b) For the operational average during the collision let's use the relationship between momentum and momentum

            I = Δp

            F Δt = m v_f - m v₀

            F = \frac{m ( v_f - v_o)}{t}

            F = m [16.66 - 31.94] / 0.815

            F = m (-18.75)

Having the force let's use Newton's second law

            F = m a

            -18.75 m = m a

             a = -18.75 m / s²

4 0
2 years ago
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