All categories

2 years ago

Velocity (m/s)

Physics

1 answer:

alekssr [168]2 years ago

3 0

Explanation:

⠀

(a) The segment A shows acceleration as velocity increases with the increase in time.

⠀

(b) The segment C shows the object is slowing down as the time increases in segment C, the velocity decreases and afterwards it comes to rest.

⠀

(c) The velocity is segment B is 40m/s. And in the diagram there is no change in velocity.

⠀

(d) The acceleration of segment B is zero. As there in no change in curve and it is moving with uniform velocity.

⠀

$\:$

<h2>Thank you!</h2>

You might be interested in

Wich of yhe following is true A mass drpendent on gravity and weight is dependent on gravity B mass is not dependent on gravity

Diano4ka-milaya [45]

C I believe is the answer

6 0

3 years ago

Read 2 more answers

Describe the relationship between joules, meters, and newtons

Naily [24]

Newton is a unit of force. Joules is an amount of work which is equal to the force times distance, or newton meters. So the product of newtons and meters makes joules.

5 0

3 years ago

The basic life function of an organism are carried on by

Lana71 [14]

I believe the answer is a: cells.

3 0

3 years ago

The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca

Verizon [17]

Answer:

The value is $E_i = 1.5596 *10^{-18} \ J$

Explanation:

From the question we are told that

The wavelength is $\lambda = 48.2 nm = 48.2 *10^{- 9 }\ m$

The velocity is $v = 2.371*10^6 \ m/s$

The mass of electron is $m_e = 9.109*10^{-31} \ kg$

Generally the energy of the incident light is mathematically represented as

$E = \frac{h * c}{\lambda}$

Here c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

h is the Planck constant with value $h = 6.62607015 * 10^{-34 } J\cdot s$

$E = \frac{6.62607015 * 10^{-34 }* 3.0 *10^{8}}{48.2 *10^{- 9 }}$

=> $E = 4.12 *10^{-18} \ J$

Generally the kinetic energy is mathematically represented as

$E_k = \frac{1}{2} * m_e * v^2$

=> $E_k = \frac{1}{2} * 9.109*10^{-31} * (2.371*10^6 )^2$

=> $E_k = 2.56 *0^{-18} \ J$

Generally the ionization energy is mathematically represented as

$E_i = 4.12 *10^{-18} - 2.56 *0^{-18}$

=> $E_i = 1.5596 *10^{-18} \ J$

7 0

3 years ago

An element from group 2 on the periodic table will bond lonically with elements from group 17(7A)

Natalija [7]

Answer:

Elements in group IIA have 2 electrons in their outermost shell so they can donate these electrons of group VII A which have seven electrons in their outermost shell. So it is necessary 2 elements of group VII A, each atoms accepts one electron.

Explanation:

8 0

3 years ago