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Aleksandr [31]
4 years ago
7

An iron nail does not pick up paper clips as a magnet would. What can be concluded about the structure of the iron nail? It has

no domains. It has domains that are not aligned. It has domains that are aligned along the nail’s length. It has domains that are aligned across the nail’s width.
Physics
2 answers:
makkiz [27]4 years ago
8 0

Answer: The correct answer is "It has domains that are not aligned".

Explanation:

The domains of the magnet are already aligned. The magnet attracts the iron nail. It will magnetized the iron nail as the domains of the iron nail gets aligned as long as it is in contact with magnet.

The magnetism will be induced in it when it is attracted to a nearby bar magnet.

In the presence of the magnetic field, the domains of the iron nail will get align. Iron is a ferromagnetic material. Then, it will become temporary magnet as long as it is in contact with the bar magnet.

It is given in the problem that an iron nail does not pick up paper clips as a magnet would. The iron nail is not magnetized. The domains of the iron nail are not aligned.

It can be concluded about the structure of the iron nail that  It has domains that are not aligned.

lesya692 [45]4 years ago
4 0

Question: An iron nail does not pick up paper clips as a magnet would. What can be concluded about the structure of the iron nail?

Answer: It has domains that are not aligned.

Explanation: because the magnet is not allined its not gonna pick up anything metal cause its not alligned

question answered by

(jacemorris04)

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Part a

Is provide that the smallest amount of energy that is needed to dissociate a molecule of a material on this case 0.42eV. We know that the energy of the photon is equal to:

E=hf

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f=\frac{c}{\lambda}

If we replace the last equation into the E formula we got:

E=h\frac{c}{\lambda}

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\lambda =\frac{hc}{E}

Using the value of the constant h=4.136x10^{-15} eVs we have this:

\lambda=\frac{4.136x10^{15}eVs (3x10^8 \frac{m}{s})}{0.42eV}=2.95x10^{-6}m

\lambda=2.95x10^{-6}m

Part b

If we see the figure attached, with the red arrow, the value for the wavelenght obtained from part a) is on the infrared region, since is in the order of 10^{-6}m

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