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4 years ago

The sum ofall microscopic forms of energy of a system is quantified as flow energy. a)True b) False

Engineering

1 answer:

Sliva [168]4 years ago

3 0

Answer: b) False

Explanation: Microscopic energy is the the energy that is based on the molecular level in a particular energy system. Microscopic energy basically comprise with tiny particles like atoms and molecules .The sum of all microscopic form of energy e together make the internal energy .Therefore, the statement given is false because the sum of all the microscopic forms of energy of a system is quantified as internal energy not flow energy.

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Show that for a linearly separable dataset, the maximum likelihood solution for the logisitic regression model is obtained by fi

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3 years ago

For surface-mounted and pendant-hung luminaires, support rods should be placed so that they extend about ____

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2 years ago

A company has a stack that emits a hazardous air pollutant. The ground mass concentration directly downwind of the plume sometim

fredd [130]

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3 years ago

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True or false a critique of hazwoper incidents that have occurred in the past year should not be included in hazwoper 8 hour ref

Jobisdone [24]

Answer:

False

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3 years ago

Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m^

Nat2105 [25]

Answer:

The answer is " $\bold{ 259.2 \times 10^{11} }$ ".

Explanation:

The amount of kilograms, which travel in a thick sheet of hydrogen:

$M= -DAt \frac{\Delta C}{ \Delta x} \\\\$

$D =1.0 \times 10^{8} \ \ \ \frac{m^2}{s} \\\\ A = 0.20 \ m^2\\\\t = 1\ \ h = 3600 \ \ sec \\\\$

calculating the value of $\Delta C:$

$\Delta C =C_A -C_B$

$= 2.4 - 0.6 \\\\ = 1.8 \ \ \frac{kg}{m^3}$

calculating the value of $\Delta X:$

$\Delta x = x_{A} -x_{B}$

$= 0 - (5\ mm) \\\\ = - 5 \ \ mm\\\\= - 5 \times 10^{-3} \ m$

$M = -(1.0 \times 10^{8} \times 0.20 \times 3600 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\$

$= -(1.0 \times 10^{8} \times 720 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\= -(1.0 \times 10^{8} \times \frac{ 1296}{-5 \times 10^{-3}})) \\\\= (1.0 \times 10^{8} \times 259.2 \times 10^3)) \\\\= 259.2 \times 10^{11} \\\\$

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3 years ago