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MakcuM [25]
3 years ago
5

The sum ofall microscopic forms of energy of a system is quantified as flow energy. a)True b) False

Engineering
1 answer:
Sliva [168]3 years ago
3 0

Answer: b) False

Explanation: Microscopic energy is the the energy that is based on the  molecular level in a particular energy system. Microscopic energy basically comprise with tiny particles like atoms and molecules .The sum of all microscopic form of energy e together make the internal energy .Therefore, the statement given is false because the sum of all the microscopic forms of energy of a system is quantified as internal energy not flow energy.

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Answer:

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Explanation:

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3 years ago
Before cutting coarse screw threads, the operator should lubricate: A. The leadscrew and gearbox B. The ways and cross slide C.
Maksim231197 [3]

Answer:

(d) all of the above

Explanation:

before cutting the screw threads the operator should lubricate all of the machine parts given in the option that is lead screw and gearbox , the ways and the cross slide and the carriage and half-nuts. we should use lubrication because it reduces the overall system friction and if friction is reduced then heat generated due to friction is also decreases which is beneficial

so option (D) will be correct because we need lubricate in all the given parts  

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2 years ago
When your hands are on home row, they are resting on the____.
MArishka [77]

Answer:

to which four fingers of each hand return as a base, on a QWERTY keyboard being A, S, D, and F for the left hand and J, K, L, and the semicolon for the right

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4 0
3 years ago
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A spacecraft at rest has moment of inertia of 100 kg-m^2 about an axis of interest. If a 1 newton thruster with a 1 meter moment
Kazeer [188]

To solve this problem we will apply the concepts related to translational torque, angular torque and the kinematic equations of angular movement with which we will find the angular displacement of the system.

Translational torque can be defined as,

\tau = Fd

Here,

F = Force

d = Distance which the force is applied

\tau = (1N)(1m)

\tau = 1N\cdot m

At the same time the angular torque is defined as the product between the moment of inertia and the angular acceleration, so using the previous value of the found torque, and with the moment of inertia given by the statement, we would have that the angular acceleration is

\tau = I\alpha

\alpha = \frac{\tau}{I}

\alpha = \frac{1N\cdot m}{100kg\cdot m^2}

\alpha = 0.01rad/s^2

Now the angular displacement is

\theta = \omega_0 t + \frac{1}{2}\alpha t^2

Here

\omega_0= Initial angular velocity

t = time

\alpha =Angular acceleration

\theta= Angular displacement

Time is given as 1 minute, in seconds will be

t = 1m = 60s

There is not initial angular velocity, then

\theta= \frac{1}{2}\alpha t^2

Replacing,

\theta= \frac{1}{2}(0.01)(60)^2

\theta = 18rad

The question neglects the effect of gravitational force.

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3 years ago
For every 3 packages that Marcella wraps she uses 1/2 of a roll of wrapping paper if she uses 2 1/2 rolls of wrapping paper how
hram777 [196]
She wrapped 5 packages
6 0
3 years ago
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