Need some help with these plz

All areas of the country use a BAC of 0.100.10 g/dL as the legal intoxication level. Is it possible that the mean BAC of all dr

vlabodo [156]

Answer:

C. Yes, and it is highly probable.

Explanation:

Null hypothesis, $H_0$ : ц 0.09

Alternative hypothesis, $H_1$ : ц > 0.09

Test statistic is,

x Z = x - ц / s

$\frac{0.15 - 0.09 }{0.06}$

$\frac{0.06}{0.06}$

=1

The p-value is,

p = P(Z > z)

=1—P(Z ≤1)

= 1— 0.841345

= 0.158655

(From normal tables)

The p-value is greater than the significance level, so we fail to reject the null hypothesis. The correct option is, C

Yes, and it is highly probable.

6 0

3 years ago

Problem 8. Define a function gs1_error(n) that accepts as input a non-negative integer n and outputs the error of the Gauss-Seid

Fofino [41]

Answer:

The MATLAB code will be:

close all;

clc;

clear all;

a = [20, 1, -2; 3, 20, -1; 2,-3, 20];

b = [17; -18; 25];

tol = 1e-6;

[M,N] = size(a);

if M~=N

error('A is not a square Matrix');

end

x = [0,0,0];

xx(1,:) = x;

n = 100;

error = 0.00001;

for k = 2:n

for i = 1:N

s = 0;

for j = 1:N

if j ~= i

s = s + a(i,j) * x(j);

end

x(i) = (1/a(i,i)*(b(i) - s));

end

xx(k,:) = x;kk = k;

Error = abs(max(xx(kk,:)- xx(k-1,:)))

if Error<error

break;

end

fprintf ('The roots of equation are: ')

x

fprintf ('The number of iterations are: ')

k

fprintf ('The error is: ')

Error

Explanation:

7 0

3 years ago

For a ceramic compound, what are the two characteristics of the component ions that determine the crystal structure?

DiKsa [7]

Answer:

The two characteristics of component ions that determine the crystal structure of a ceramic compound are:

1) The magnitude of electrical charge on each ion.

2) The relative sizes of both cations and anions.

Explanation:

Most ceramics normally contain both metallic and nonmetallic elements with ionic or covalent bonds. Thus, the structure of the metallic atoms, structure of the non-metallic atoms, and also the balance of charges produced by the valence electrons must be considered.

These ionic and covalent bonds i talked about earlier are the strong primary bonds that hold the atoms together and form the ceramic material. These chemical bonds are of two types:

i) they could either be ionic in character, meaning they involve a transfer of bonding electrons from electropositive atoms (cations) to electronegative atoms (anions),

ii) or they could be covalent in character, which involves orbital sharing of electrons between the constituent atoms or ions.

Thus, Covalent bonds are generally directional in nature, often dictating the types of crystal structure possible. Whereas, Ionic bonds, on the other hand, are entirely nondirectional. This nondirectional nature allows for hard-sphere packing arrangements of the ions into a variety of crystal structures.

So, we can deduce that;

The two characteristics of component ions that determine the crystal structure of a ceramic compound are:

1) The magnitude of electrical charge on each ion.

2) The relative sizes of both cations and anions.

3 0

3 years ago

Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 43.1 deg

Marysya12 [62]

Answer:

resolved shear stress = 22.0 MPa

so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa

Explanation:

given data

angles φ = 43.1 degrees

angles λ = 47.9 degrees

shear stress = 20.7 MPa (3000 psi)

stress σ = 45 MPa (6500 psi)

solution

we have given shear stress so first we calculate here resolved shear stress that is express as

resolved shear stress = σ cosφ cosλ .................1

here σ is stress and φ and λ are angles given

so put here value we get

resolved shear stress = σ cosφ cosλ

resolved shear stress = 45 cos(43.1) cos(47.9)

resolved shear stress = 22.0 MPa

so we can say that here single crystal will yield because critical resolved shear stress i.e 20.7 MPa is less than resolved shear stress i.e 22.0 MPa

4 0

3 years ago

Interpret the assembly program below: MOV R3,R0;

Reika [66]

Answer:

Explanation:

1. With the operands R0, R1, the program would compute AND operation and ADD operation .

2. The operands could truly be signed 2's complement encoded (i.e Yes) .

3. The overflow truly occurs when two numbers that are unsigned were added and the result is larger than the capacity of the register, in that situation, overflow would occur and it could corrupt the data.

When the result of an operation is smaller in magnitude than the smallest value represented by the data type, then arithmetic underflow will occur.

7 0

4 years ago