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Oksanka [162]
3 years ago
8

State two main consumers of electricity transmitted at low frequency Calculate the primary voltage of a transformer if the prima

ry winding is 50 turns and the secondary winding is 150 turns with 450 volts.
Engineering
2 answers:
bagirrra123 [75]3 years ago
7 0

Answer:

1) a. Customers requiring AC electric power transmission for powering remote devices which may include a subsea transmission system where power is distributed to subsea devices

b. Customers that utilize commutator-type motors

2) The primary voltage is 150 volts

Explanation:

The parameters given are;

Number of primary winding, N_p = 50 turns

Number of secondary winding, N_s = 150 turns

Voltage in secondary winding, V_s = 450 volts

Voltage in primary winding = V_p

The relation between N_p, N_s, V_s and V_p is as follows;

\dfrac{V_p}{V_s}  = \dfrac{N_p}{N_s}

Which gives;

V_p  = \dfrac{N_p \times V_s}{N_s}

From which we have;

V_p  = \dfrac{50\times 450}{150} = 150 \ volts

The primary voltage = 150 volts.

NikAS [45]3 years ago
3 0
What he/she said ^^^^^^^^
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2 years ago
The size of Carvins Cove water reservoir is 3.2 billion gallons. Approximately, 11 cfs of water is continuous withdrawn from thi
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Answer:

471 days

Explanation:

Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons

As,  

1 gallon = 0.133 cubic feet (cf)

Therefore,  

Capacity of Carvins Cove water reservoir in cf  = 3.2 x 10˄9 x 0.133

                                                                         = 4.28 x 10˄8

 

Applying Mass balance i.e

Accumulation = Mass In - Mass out   (Eq. 01)

Here  

Mass In = 0.5 cfs

Mass out = 11 cfs

Putting values in (Eq. 01)

Accumulation  = 0.5 - 11

                         = - 10.5 cfs

 

Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.

Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600

                                                                                       = 37,800

 

Converting depletion of reservoir in cubic feet per day = 37, 800 x 24

                                                                                         = 907,200  

 

i.e. 907,200 cubic feet volume is being depleted in days = 1 day

1 cubic feet volume is being depleted in days = 1/907,200 day

4.28 x 10˄8 cubic feet volume will deplete in days  = (4.28 x 10˄8) x                    1/907,200

                                                                                 = 471 Days.

 

Hence in case of continuous drought reservoir will last for 471 days before dry-up.

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