4 years ago

Which is an example of a physical change

Physics

1 answer:

cupoosta [38]4 years ago

4 0

Answer:

ice forming and then melting back into water

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Rae has just heard a loud crash from her garage. The impact of the sound wave bouncing against her eardrum sets off a chain reac

matrenka [14]

Answer:

Hammer

Anvil

Stirrup

Explanation:

The three tiny bones in the ear drum are:

Hammer, this is also known as malleus and it is attached to the eardrum

Anvil, this is also called incus and it found with the chain of bones in the middle ear.

Stirrup, also known as stapes and it attached to the membrane covered opening that connects the middle ear with the inner ear.

7 0

3 years ago

The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8. What is the ideal efficiency of the engine? Use

vodomira [7]

Answer:

e=58%

Explanation:

Given data

The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8.

Solution

We want to calculate the ideal efficiency of the engine when ratio of heat capacity for gas used γ=1.40. Ideal efficiency (e) of the Otto cycle given by:

$e=1-(\frac{1}{r^{Y-1} } )\\$

Substitute the given values to find efficiency e

$e=1-\frac{1}{8.8^{1.4-1} } \\e=0.58\\$

e=58%

8 0

3 years ago

1. Определите, используя график, удельную теплоемкость жидкости, если на плавление и нагревание до 65 градусов 1 кг вещества был

Sholpan [36]

translate it to english

Explanation:

6 0

3 years ago

A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.

Gekata [30.6K]

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] = $6.5*10^{4}\ m/s$

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity $[\theta]$ = 15 degree.

We are asked to calculate the magnetic force experienced by the charged particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force $\vec F=q(\ \vec V \times \vec B)$

i.e F = $=qVBsin\theta$

$=6.8*6.5*10^{4}*1.4*sin15$

$=61.88*10^{4}sin15$

$=61.88*10^4*0.2588\ N$

$=16.016*10^4\ N$

$=1.6*10^5\ N$

Hence, the force experienced by the charged particle is C i.e $1.6*10^5 N$

4 0

3 years ago

Read 2 more answers

What is the force of an object with a mass of 65 kg and an an unknown acceleration?

Alik [6]

We know, F = m.a

F = 65 * a

Where, F = force

a = unknown acceleration

8 0

4 years ago