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3 years ago

14

you throw a rock with a horizontal velocity at 36.6 m/s out a window that is 29.5 m above the ground. What was it’s total time i

n the air?

1 answer:

ANEK [815]3 years ago

4 0

29.5-4.9x^2= your answer

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A man steps out of a plane at a height of 4000 m above the ground, falls

lidiya [134]

Ch to C k it b be no

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3 years ago

Two concentric conducting spherical shells produce a radially outward electric field of magnitude49,000 N/C at a point 4.10 m fr

Korolek [52]

To solve this problem it is necessary to apply the concepts related to the electric field according to the definition of Coulomb's law.

The electric field is defined mathematically as a vector field that associates to each point in space the (electrostatic or Coulomb) force per unit of charge exerted on an infinitesimal positive test charge at rest at that point.

Mathematically this can be described as:

$E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}$

Where,

$\epsilon_0 =$ permittivity of free space

r = Distance

q = Charge

E = Electric Field

Our values are given as,

$E= 49.000N/C$

$r= 4.1m$

$\epsilon_0=8.854*10{-12}C^2N^{-1}m^{-2}$

Replacing we have,

$E = \frac{1}{4\pi \epsilon_0}\frac{q}{r^2}$

$49000 = \frac{1}{4\pi (8.854*10{-12})}\frac{q}{(4.1)^2}$

$q= 9.16*10^{-5} C$

$q= 91.6\mu C$

Therefore the amoun of charge on the outer surface of the larger shell is $91.6 \mu C$

6 0

3 years ago

Which of the following is not a valid use of your driver's license?

Ilya [14]

Answer:

Proof that you have liability insurance

Explanation:

8 0

3 years ago

A 3.4 nC charged particle has a velocity of 4.7 m/s and is moving in the +x-direction. If this charge is in a magnetic field det

zloy xaker [14]

Answer:

Magnetic force, $F=1.22\times 10^{-7}\ N$

Explanation:

It is given that,

Charge, $q=3.4\ nC=3.4\times 10^{-9}\ C$

Velocity, v = 4.7 m/s

Magnetic field, $B=-1.4i+7.52j$

$|B|=\sqrt{(-1.4)^2+(7.52)^2}=7.64\ T$

Magnetic force is given by :

$F=q\times v\times B$

$F=3.4\times 10^{-9}\ C\times 4.7\ m/s\times 7.64\ T$

$F=1.22\times 10^{-7}\ N$

So, the magnetic force on this particle is $1.22\times 10^{-7}\ N$ . Hence, this is the required solution.

5 0

3 years ago

A resistor rated at 690 kΩ is connected across two D cell batteries (each 1.50 V) in series, with a total voltage of 3.00 V. The

MrRa [10]

Answer:

The possible minimum current and maximum current through the resistor is 4.53 μA and 4.18 μA

Explanation:

Given that,

Resistance = 690 kΩ

Total voltage = 3.00 V

We need to calculate the maximum resistance

$R_{max}=690000+(\dfrac{4}{100}\times690000)$

$R_{max}=717600\ \Omega$

We need to calculate the minimum resistance

$R_{min}=690000-(\dfrac{4}{100}\times690000)$

$R_{min}=662400\ \Omega$

We need to calculate the maximum and minimum current

Using ohm's law

For maximum current,

$V = I R$

$I_{max}=\dfrac{V}{R_{max}}$

$I_{max}=\dfrac{3.00}{717600}$

$I_{max}=0.00000418\ A$

$I_{max}=4.18\times10^{-6}=4.18\ \mu A$

For minimum current,

$I_{max}=\dfrac{3.00}{662400}$

$I_{min}=0.00000453\ A$

$I_{min}=4.53\times10^{-6}= 4.53\ \mu A$

Hence, The possible minimum current and maximum current through the resistor is 4.53 μA and 4.18 μA

3 0

3 years ago