Answer: time t = 10s
Explanation:
Given;
Diameter = 8.0cm = 0.08m
Radius r = diameter/2 = 0.08/2 = 0.04m
Cord length d = 6.0m
Angular acceleration = 3.0rads/s2
Time = t
Converting the angular acceleration to linear acceleration
a = a* × r = 3.0 × 0.04 = 0.12m/s
d = vt + 1/2 (a × t^2)
Initial velocity v = 0, vt = 0 therefore;
d = 1/2 ( a × t^2)
t = √(2d/a)
t = √ [(2× 6)/0.12]
t = 10s
<h3>
Answer:</h3>
539.56 Joules
<h3>
Explanation:</h3>
- Efficiency of a machine is the ratio of work output to work input expressed as a percentage.
- Efficiency = (work output/work input) × 100%
- Efficiency of a machine is not 100% because so energy is lost due to friction of the moving parts and also as heat.
In this case;
Efficiency = 94%
Work input = 574 Joules
Therefore, Assuming work output is x
94% = (x/574 J) × 100%
0.94 = (x/574 J)
<h3>x = 539.56 J</h3>
Thus, you get work of 539.56 J from the machine
Answer:
by making observation hope it's helpful
Answer:
no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.
