You need to look at the electronegativity and decide wheter the difference of both of the numbers are significant enough to form a polar bond
Answer:
24.7 amu
Explanation:
An isotope is when an element can have different number of neutrons but they have same number of protons.
In order to calculate the average atomic mass with the given information do the following operations:
First change de percentages to fractional numbers, divide by 100.
I like to make a table, to organize all data and I believe is easier to understand.
65/100 = 0.65
35/100 = 0.35
% fraction
65.0 0.65
35.0 0.35
total100.0 1
Now multiply each mass with their corresponding fraction
24 (0.65) = 15.6
26 (0.35) = 9.1
% fraction uma uma
65.0 0.65 24 15.6
35.0 0.35 26 9.1
total100.0 1 24.7
Finally you add the resulting mass and the units will be in uma.
15.6+9.1 = 24.7
Therefore the average atomic mass of this element will be 24.7 uma.
Check the table in the document attached
Lower the melting point
Explanation:
Salts helps to melt road by lowering the melting point. It acts as an impurity and generally, impurities low the melting point of substances.
Salts are used as an antifreeze.
- Water freezes at 0°C and forms ice/snow which can impede human and vehicular movement.
- When salt is added, it causes the depression of the freezing point by lowering it further.
- The freezing point is pegged back at -6°C.
- This way it takes more low temperature to freeze the water.
- The salt acts as an impurity and causes the depression of melting point and widening of the melting range.
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B) oxygen, because oxygen is the only element that is in both chemical formulas.
A) Answer D. Clouds forming high in the atmosphere are referred to as cirrus, cirrostratus, and cirrocumulus.
B) Clouds tend to form at higher altitudes because as<span> air rises, the moisture in it slowly reaches its saturation point and when this happens, tiny crystals of water start to condense and form clouds.
C) Precipitation: Water that falls to the ground from clouds, such as in rain, snow, sleet, or hail.</span>