In 11.06 grams of C5H11OH how many grams of water can be produced?

¿Qué volumen ocuparán 12 g de hierro?

sasho [114]

Answer:

$\large\boxed{\large\boxed{volume=1.5cm^3}}$

Explanation:

Translation:

What volume will 12g of iron occupy?

<h2>Solution</h2>

Iron is a solid substance at room temperature. You can find the volume of solids (and of not solids) using the density.

$Density=\dfrac{mass}{volume}$

You can obtaindthe density of most pure substances in the internet. The density of iron at room temperature is 7.874 g/cm³.

Thus, substituting in the formula, you get:

$7.874g/cm^3=\dfrac{12g}{volume}\\ \\ \\ volume=\dfrac{12g}{7.874g/cm^3}\\ \\ \\ volume=1.5cm^3$

The answer is rounded to two significant figures because the input, 12g, has two significant figures.

8 0

3 years ago

Sulfuric acid, H2SO4, can be neutralized by sodium hydroxide, NaOH. The unbalanced equation is: H2SO4(aq) + NaOH(aq) → Na2SO4(aq

evablogger [386]

Answer: Sulfuric acid, H2SO4, can be neutralized by sodium hydroxide, NaOH. The unbalanced equation is:
H2SO4(aq) + NaOH(aq) → Na2SO4(aq) + H2O(l)
A student who was asked to balance the reaction wrote the following:
H2SO4(aq) + Na2OH(aq) →Na2SO4(aq) + H3O(l)
Is this correct? Explain why or why not using what you know about the law of conservation of mass and chemical changes. If necessary, provide the correct balanced equation.
Explanation: The mass of the reactants must equal that of the products. This is because the masses of the products arise from the reactants and no mass is either created or destroyed. The total mass of the reactant must equal that of the product side and vice versa.
The student made an error of protonating the water molecule to H3O+ without a corresponding balance on the reactant side. In this case, it is wrong and ceases to be an equation. The product side masses don't equal the reactant side.
Balancing a chemical equation is done by first writing the correct chemical symbol. The moles and masses of each compound are cross-checked that they are equal on both sides of the equation.

3 0

2 years ago

What is the mass of solid NH4Cl formed when 75.5g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas remai

taurus [48]

Answer:The volume of the remaining gas that is ammonia is 23.85 L.

Explanation:

$NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)$

Moles of $NH_3=\frac{\text{mass of} NH_3}{\text{Molar mass of}NH_3}=\frac{75.5 g}{17.03 g/mol}=4.43 mole$

Moles of HCl of gas = $\frac{\text{mass of} HCl}{\text{Molar mass of}HCl}=\frac{75.5 g}{36.5 g/mol}=2.06 mol$

According to reaction 1 mole of HCl reacts with 1 mol of $NH_3$ then 2.06 moles of HCl will react with = 2.06 moles of $NH_3$

Moles left of ammonia left = 4.43 - 2.06 = 2.36 moles

Volume of the gas will be given by Ideal gas equation: PV=nRT

Pressure = 752 mmHg = 752 × 0.0031 atm = 2.33 atm

R = 0.08026 L atm/K mol

V = ? , n = number of moles of ammonia

Temperature = 14 °C = 14 + 273 K = 287 K(0°C = 273K)

$V=\frac{2.36 mol\times 0.08206 L atm/K mol\times 287 K}{2.33 atm}=23.85 L$

The volume of the remaining gas that is ammonia is 23.85 L.

8 0

2 years ago

Read 2 more answers

How many grams of Cl2 will be produced along with 250.0 kJ of heat in the following reaction? PCl5(g) + 87.9 kJ PCl3(g) + Cl2(g)

AfilCa [17]

250 kJ/87.9 KJ per mole Cl2 * 71g/mole= 202 g It is D for plato users

3 0

2 years ago

Read 2 more answers

An irregular chunk of iron has a density of 7.87 g/cm3. A 14.5 gram chunk is added to a graduated cylinder. If the final volume

bulgar [2K]

Answer:

37.96 mL

Explanation:

From the question given above, the following data were obtained:

Density (D) of iron = 7.87 g/cm³

Mass (m) of iron = 14.5 g

Volume of Cylinder + Iron = 39.8 mL

Volume of Cylinder =?

Next, we shall determine the volume of the chunk of iron. This can be obtained as follow:

Density (D) of iron = 7.87 g/cm³

Mass (m) of iron = 14.5 g

Volume (V) of iron =?

D = m/V

7.87 = 14.5 /V

Cross multiply

7.87 × V = 14.5

Divide both side by 7.87

V = 14.5 / 7.87

V = 1.84 cm³

Recall:

1 cm³ = 1 mL

Therefore,

1.84 cm³ = 1.84 mL

Therefore, the volume of the chunk of iron is 1.84 mL.

Finally, we shall determine the starting volume of the cylinder as follow:

Volume of Cylinder + Iron = 39.8 mL

Volume of Iron = 1.84 mL.

Volume of Cylinder =?

Volume of Cylinder = (Volume of Cylinder + Iron) – Volume of Iron

Volume of Cylinder = 39.8 – 1.84

Volume of Cylinder = 37.96 mL

Therefore the starting volume of cylinder is 37.96 mL

3 0

2 years ago