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-Dominant- [34]
3 years ago
10

A worker pushes a large rock to the north while another worker helps by pushing it to the east. If they both exert equal force,

in what direction does the rock move?
Question 2 options:

northeast

east

north

southwest
Physics
1 answer:
alexandr1967 [171]3 years ago
3 0

let the magnitude of force applied by each worker be "F"

consider east-west direction along X-axis and north-south direction along Y-axis

In unit vector form, force vector by worker pushing in east direction is given as

\underset{A}{\rightarrow} = F \hat{i} + 0  \hat{j}


In unit vector form, force vector by worker pushing in north direction is given as

\underset{B}{\rightarrow} = 0 \hat{i} + F  \hat{j}

resultant force is given as the vector sum of two vector forces as

\underset{R}{\rightarrow} = \underset{A}{\rightarrow} + \underset{B}{\rightarrow}

\underset{R}{\rightarrow} = (F \hat{i} + 0  \hat{j} ) + (0 \hat{i} + F  \hat{j} )

\underset{R}{\rightarrow} = F \hat{i} +  F  \hat{j}

direction of the force is hence given as

θ = tan⁻¹(F/F)

θ =  tan⁻¹(1)

θ = 45 degree north of east

hence the direction is north-east


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