let the magnitude of force applied by each worker be "F"
consider east-west direction along X-axis and north-south direction along Y-axis
In unit vector form, force vector by worker pushing in east direction is given as
= F
+ 0
In unit vector form, force vector by worker pushing in north direction is given as
= 0
+ F
resultant force is given as the vector sum of two vector forces as
=
+
= (F
+ 0
) + (0
+ F
)
= F
+ F
direction of the force is hence given as
θ = tan⁻¹(F/F)
θ = tan⁻¹(1)
θ = 45 degree north of east
hence the direction is north-east