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-Dominant- [34]
3 years ago
10

A worker pushes a large rock to the north while another worker helps by pushing it to the east. If they both exert equal force,

in what direction does the rock move?
Question 2 options:

northeast

east

north

southwest
Physics
1 answer:
alexandr1967 [171]3 years ago
3 0

let the magnitude of force applied by each worker be "F"

consider east-west direction along X-axis and north-south direction along Y-axis

In unit vector form, force vector by worker pushing in east direction is given as

\underset{A}{\rightarrow} = F \hat{i} + 0  \hat{j}


In unit vector form, force vector by worker pushing in north direction is given as

\underset{B}{\rightarrow} = 0 \hat{i} + F  \hat{j}

resultant force is given as the vector sum of two vector forces as

\underset{R}{\rightarrow} = \underset{A}{\rightarrow} + \underset{B}{\rightarrow}

\underset{R}{\rightarrow} = (F \hat{i} + 0  \hat{j} ) + (0 \hat{i} + F  \hat{j} )

\underset{R}{\rightarrow} = F \hat{i} +  F  \hat{j}

direction of the force is hence given as

θ = tan⁻¹(F/F)

θ =  tan⁻¹(1)

θ = 45 degree north of east

hence the direction is north-east


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Answer:

F = 69.5 [N]

Explanation:

We must remember that the friction force is defined as the product of the normal force by the coefficient of friction, and it can be calculated by the following expression.

f=N*miu

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f = friction force = 22 [N]

Now we must calculate the force exerted by means of Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

F - f = m*a

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F = force exerted [N]

f = friction force [N]

m = mass = 95 [kg]

a = acceleration = 0.5 [m/s²]

Now replacing:

F - 22 = 95*0.5\\F = 47.5 + 22\\F = 69.5 [N]

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Answer:

ΔS total ≥ 0 (ΔS total = 0 if the process is carried out reversibly in the surroundings)

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the total entropy change will be

ΔS total = ΔS al + ΔS surr

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A block is resting on a platform that is rotating at an angular speed of 2.4 rad/s. The coefficient of static friction between t
Sloan [31]

Answer:

r = 0m is the Minimum distance from the axis at which the block can remain in place wothout skidding.

Explanation:

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N - m*g = 0   So, N = m*g.   Replacing everything on the original equation:

\mu*m*g = m*\omega^2*r   (eq2)

Solving for r:

r = \frac{\mu*g}{\omega^2}=1.41m

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Answer:

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