Question

A block of mass 4 kg rests on a horizontal surface without friction, when subjected to the action of 5 horizontal forces as shown in the figure (wait for the figure). Answer: (a) How strong is the resulting force? (b) What is the direction of the resulting force? (c) If the block takes action to come out of inertia, what will be its acceleration acquired?

Answer 1

Answer:

a) F = 40 N

b) It is acting towards left

c) a = 10 m/s²

Explanation:

As the block of mass and its forces are not shown, the question is incomplete.

First we attach the diagram of the attached question (See below)

We can see in the diagram that there are total of 5 forces acting on that block. Consider the forces acting towards right to be positive and the forces acting towards left be negative (or vice versa, the answer would be same). Let them be:

F₁ = 10 N

F₂ = 17 N

F₃ = 21 N

F₄ = -35 N

F₅ = -53 N

(a)

To find resultant force, we'll add all of the 5 forces.

Resultant Force = F₁ + F₂ + F₃ + F₄ + F₅

Resultant Force = 10 + 17 +21 - 35 - 53

Resultant Force = -40 N

(b)

As the resultant force has a negative sign, and previously we stated that the forces acting towards left are negative, so the Resultant Force is acting in the left direction.

(c)

We know that

F = (m)(a)

Where F is the resultant force we found. Resultant Force was -40N , where negative sign only represents the direction. We'll consider only the magnitude which is 40N, where m is the mass of the block which is 4 kg. Substitute in the equation.

40 = (4)(a)

a = (40)(4)

a = 10 m/s² (in left direction)