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oee [108]
3 years ago
7

if a car is moving on a highway at 70 kilometers per hour going east, what happens to its speed and velocity ​

Physics
1 answer:
Andrej [43]3 years ago
7 0
The speed is constant since there is no opposite force facing the car

That’s my best guest hope it helps !! :)
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9. [03.03]
Evgen [1.6K]

Answer:

Circuit one will have more current than circuit two

Explanation:

I am assuming that you have to see which circuit has the greater current in this case. Well, this is the perfect example of Ohm's Law, which states the following -

V = IR,

where V = voltage / potential difference, I = current, and R = resistance

If one circuit has twice the voltage and half the resistance of the second circuit, as voltage is directly proportional to the resistance -

2V = I( 1 / 2R ),

4V = IR,

I = 4V / R

Whereas in the second circuit -

V = IR,

I = V / R

As you can note, voltage is directly proportional to the current ( I ) as well as the resistance. The only difference between the two formulas I = 4V / R, and I = V / R is the difference in the voltage. With the voltage being 4 times greater in the first circuit, and current is 4 times greater in the first circuit as well.

<u><em>Hence, circuit one will have more current than circuit two</em></u>

5 0
4 years ago
Read 2 more answers
11) The total conversion of 2.50 kilogram of the
Elanso [62]

1.41 × 10³⁰ MeV

As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).

Given mass = 2.5 kgs

∴ E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J

As our answer is in joules so we have to convert it into mega electron volt(MeV)

1 J = 6.242 × 10¹² MeV

⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV

⇒1.41 × 10³⁰ MeV

If you want to learn more about mass-energy conversions then you can check out this link:

https://brainly.in/question/9760064

3 0
2 years ago
Read 2 more answers
Please someone helppp me.. I will mark as brainliest.​
Mademuasel [1]

Answer:

b) G.P.E = Mgh

300j = M x 10 m/s² x 15 m

300 j/ 10 m/s² x 15 m = M

300j/ 150 s² = M

2kg = M

c) K.E = 1/2 m v²

K.E = 1/2 (50) (50)²

K.E = 1/2 (50) (2500)

K.E= 125000/2

K.E = 625 000 J

4 0
3 years ago
A bar-magnet with magnetic moment 2.5 Am^2 is placed in a homogeneous magnetic field (of 0.1 T that is directed along the z-axis
Angelina_Jolie [31]

Answer:

1)

Force on bar magnet  = 0

Torque on bar magnet = 0

2)

Force on bar magnet  = 0

Torque on bar magnet = 0.177 Nm

3)

Force on bar magnet  = 0

Torque on bar magnet = 0.25 Nm

Explanation:

Part 1)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is inclined along z axis along magnetic field

then we will have

\tau = MBsin0 = 0

Part 2)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is pointing 45 degree with z axis then we will have

\tau = MBsin45

\tau = (2.5)(0.1)sin45

\tau = 0.177 Nm

Part 3)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

\tau = MBsin\theta

when bar magnet is pointing 90 degree with z axis then we will have

\tau = MBsin90

\tau = (2.5)(0.1)sin90

\tau = 0.25 Nm

8 0
4 years ago
What is the net force in this image?
9966 [12]

Net force on the image is 0 Newton.

<h3>What is force?</h3>

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Net upward force is balanced by net downward force so net force is zero.

Net force on the image is 0 Newton.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ1

6 0
1 year ago
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