Answer:
202.8m
Explanation:
Given that A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 120 m/s. He misses his target and the cannonball splashes into the briny deep.
First calculate the total time travelled by using the second equation of motion
h = Ut + 1/2gt^2
Let assume that u = 0
And h = 3.5
Substitute all the parameters into the formula
3.5 = 1/2 × 9.8 × t^2
3.5 = 4.9t^2
t^2 = 3.5/4.9
t^2 = 0.7
t = 0.845s
To know how far the cannonball travel, let's use the equation
S = UT + 1/2at^2
But acceleration a = 0
T = 2t
T = 1.69s
S = 120 × 1.69
S = 202.834 m
Therefore, the distance travelled by the cannon ball is approximately 202.8m.
Answer:
buoyant force on the block due to the water= 10 N
Explanation:
We know that
buoyant force(F_B) on a block= weight of the block in air (actual weight) - weight of block in water.
Given:
A block of metal weighs 40 N in air and 30 N in water.
F_B = 40-30= 10 N
therefore, buoyant force on the block due to the water= 10 N
The correct answer would be a) head of state.
Chief executives carry out executive orders.
The commander in chief carries out military orders and commands military forces. Leaders of foreign policy deal enforce international policies.
Answer:
a) Δp = - 10113.2 Kg m / s, b) he rate of change is negative, c) F = 140.46N
Explanation:
a) For this part let's analyze a water particle, it has a velocity of 66 m / s and when it collides with the building its velocity changes to zero, so the change in moment is
Δp = mv_f - m v₀
Δp = -m v₀ (1)
the change of the moment in a second is
if 2429 gallons arrive in in minute (60s) in a second how many gallons arrive
c_agua = 2429/60
c_water = 40,483 gallon/ s
let's use the concept of density to find the mass
ρ = m / V
m = ρ V
let's reduce gallons to liters
c_water = 40,483 gal (3,785 l / 1 gal) = 153.23 l
m = 1 153.23
m 153.23 kg
we substitute in 1
Δp = - 153.23 66
Δp = - 10113.2 Kg m / s
b) From the previous result the rate of change is negative
c) Let's use the impulse ratio
I = f t = Δp
F t = Δp
F = Δp / t
F = 
F = 140.46 N
