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Iteru [2.4K]
3 years ago
11

Select an incorrect statement relating to a Carnot cycle operating on a gas. A) Each process is a reversible process. B) work oc

curs for all four processes. C) there are two adiabatic processes. D) There are two constant-pressure processes.
Physics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

B)

D)

Explanation:

Carnot cycle ;

  This is the ideal cycle for all type of heat engine.All the process in the Carnot cycle is reversible processes ( those process does not leave any effect on the system as well as surrounding when the process is  reversed  is known as reversible process).It have four process in which two process is constant temperature and other two is isentropic or we can say that reversible adiabatic.

In the two process(constant temperature) only heat interaction take places and other two process(adiabatic) only work interaction take places.

So the option B and D is incorrect for Carnot cycle.

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Uranium-235 has 92 protons. How many neutrons does it have?
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Answer:

146 neutrons.

Explanation:

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The figure shows a water-filled syringe with a 4.0-cm-long needle. What is the gauge pressure of the water at the point P, where
mars1129 [50]

Answer:

Pressure at P point is given as

P_p = 1.042 \times 10^5 Pa

Explanation:

As we know by poiseuille's equation of viscous flow of liquid through cylindrical pipe

Q = \frac{\Delta P \pi r^4}{8\eta L}

here we know that

L = 4 cm

\eta = 1 \times 10^{-3} Pa s

r = 1 mm

Q = flow rate

\pi r^2 v = \frac{\Delta P \pi r^4}{8\eta L}

v = \frac{\Delta P r^2}{8 \eta L}

10 = \frac{\Delta P (10^{-3})^2}{8(1 \times 10^[-3})(0.04)}

3.2 \times 10^{-3} = \Delta P (10^{-6})

\Delta P = 3.2 \times 10^3 Pa

now we have

P_p - P_{atm} = 3.2 \times 10^3

P_p = 1.01 \times 10^5 + 3.2 \times 10^3

P_p = 1.042 \times 10^5 Pa

8 0
3 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f
Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

u = 0m/s

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

s = ut+\frac{1}{2} at^2

Replacing,

1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2

u =6.4013m/s

The height of the acorn above the meter stick can be calculated as,

v^2 = u^2 +2gh

h = \frac{v^2-u^2}{2g}

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h = 2.0906+1.87

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4 0
4 years ago
his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadi
zepelin [54]

Answer:

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PART B) For the exit area we need to arrange the equation in function of Area, that is

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