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Iteru [2.4K]
2 years ago
11

Select an incorrect statement relating to a Carnot cycle operating on a gas. A) Each process is a reversible process. B) work oc

curs for all four processes. C) there are two adiabatic processes. D) There are two constant-pressure processes.
Physics
1 answer:
nekit [7.7K]2 years ago
4 0

Answer:

B)

D)

Explanation:

Carnot cycle ;

  This is the ideal cycle for all type of heat engine.All the process in the Carnot cycle is reversible processes ( those process does not leave any effect on the system as well as surrounding when the process is  reversed  is known as reversible process).It have four process in which two process is constant temperature and other two is isentropic or we can say that reversible adiabatic.

In the two process(constant temperature) only heat interaction take places and other two process(adiabatic) only work interaction take places.

So the option B and D is incorrect for Carnot cycle.

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Answer:

yes; yes

Explanation:

Phases of the moon refers to the shapes of the moon due to the lit part of it visible from the Earth. On a new moon day, the moon comes between the sun and the earth such that the lit portion is not visible from the Earth. On a full moon day, the earth comes between the sun and the moon and the whole lit part is visible.

When one would view the earth from the moon, the earth would also be visible as going through the phases. The order would be reversed. Understand this with the following example, On a new moon day, the Earth would be visible completely lit from the moon. So it will be full Earth day on the moon. On a full moon day, the lit side of the Earth would be completely away and hence, from the moon, new earth would be there.

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Which of the following sets of words are not related
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Explanation:

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3 years ago
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What happens to the acceleration of an object if the net force on it increases
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Two balls have masses 18 kg and 47 kg. The 18 kg ball has an initial velocity of 76 m/s (to the right) along a line joining the
BigorU [14]

Answer:

The final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

Explanation:

Mass of first ball m_{1} = 18 kg

Mass of second ball m_{2} = 47 kg

Initial velocity of 18 kg ball V_{1} = 76 \frac{m}{sec}

Initial velocity of 47 kg ball = 0

Final velocity of 18 kg ball V_{2} = ??

Final velocity of 18 kg ball  is given by the formula

V_{2} = \frac{2 m_{1} V_{1} }{m_{1} + m_{2}  }

Put all the values in above formula we get

V_{2} = 2 × 18 × \frac{76}{65}

V_{2} = 42.09 \frac{m}{sec}

Thus, the final velocity of 18 kg ball is V_{2} = 42.09 \frac{m}{sec}

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2 years ago
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