Answer:
D. Time and pressure changes dead plant material to peat.
Explanation:
There are four steps in the production of coal: peat, lignite, bituminous and anthracite.
Peat: in this stage dead plants are oxidized to water and carbon dioxide and buried under sediments. The partial decomposition of plant matter due to the absence of oxygen is called peat. There is no factor of time and pressure that changes dead plant material to peat.
Lignite: Peat is subjected to heat, pressure, and time to form lignite.
Bituminous: More pressure in lignite removes all the traces of plant matter and form “soft coal”, bituminous coal.
Anthracite: It is the last stage, in which hard coal forms with the combined pressure and high temperature.
Hence, the correct answer is "D. Time and pressure changes dead plant material to peat."
True i really don’t feel like giving an explanation but trust me it’s trye
We have to solve this question using the stoichiometry of the reaction:
The equation of the reaction is;

According to the question;
Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles
From the stoichiometry of the reaction:
Since;
24 moles of CO2 released 15,026 KJ
0.48 moles of CO2 will release 0.48 * 15,026/24
= 301 KJ of heat.
brainly.com/question/6901180
<u>Answer:</u> The amount of sample left after 20 years is 288.522 g and after 50 years is 144.26 g
<u>Explanation:</u>
We are given a function that calculates the amount of sample remaining after 't' years, which is:

Putting values in above equation:


Hence, the amount of sample left after 20 years is 288.522 g
Putting values in above equation:


Hence, the amount of sample left after 50 years is 144.26 g