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3 years ago

Which of the following gases effuses most rapidly?

Chemistry

1 answer:

wariber [46]3 years ago

8 0

Answer:

C. Carbon monoxide

This is my answer tell me if wrong

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H2SO4 + 2NaOH → 2H2O + Na So.

gayaneshka [121]

Answer:

2 mol H

Explanation:

For every 2 mol of NaOH, we're reacting 2 mol of H2O. In order to figure out how many mol of H are needed, it needs to be set up stochiometrically. Starting off with the given value, 1 mol of NaOH, we can then make a mol to mol ratio. For 2 mol of NaOH, we have 2 mol of H2O. For every 2 mol of H2O, we have 4 mol of H (this is because we are multiplying the coefficient by the subscript: 2 × 2). Now, we can solve for our answer.

1 mol NaOH × (2 mol H₂O / 2 mol NaOH) × (4 mol H / 2 mol H₂O)

= 2 mol H

Thus, we get 2 mol of H are needed to completely react 1 mol of NaOH.

7 0

3 years ago

A hydrobromic acid (HBr) solution has a molar concentration of 0.055 M, Calculate the and pH of the solution. (Remember that Kw=

seraphim [82]

Answer: Im not sure but i think its B

Explanation: Its hard to explain so im

not gonna do it

5 0

3 years ago

Please help, i need help! it’s for chemistry!

viktelen [127]

Sodium - metallic bonding

Oxygen - covalent bonding

Sodium chloride - ionic bonding

Magnesium oxide - ionic bonding

Nitrogen fluoride - covalent bonding

Aluminium - metallic bonding

Calcium hydroxide - ionic bonding

Silicon fluoride - covalent bonding (not 100% sure on this one)

Chlorine - covalent bonding

Potassium oxide - ionic bonding

7 0

3 years ago

What is the smallest particle of an element that still retains all the properties of the element? a compound a mineral an atom a

nasty-shy [4]

The atom is the smallest particle of an element that retains it's characteristics. Sub-atomic particles such as protons, neutrons and electrons form the atom and it is the amount of each of these sub-atomic particles that make the element that element.

7 0

3 years ago

Read 2 more answers

Click the "draw structure" button to launch the drawing utility. under certain reaction conditions, 2,3−dibromobutane reacts wit

REY [17]

Answer:

Explanation:

According to this. Let's analize the possible products a, b and c.

First, the problem states that we have 2 eq. of base, For this case, let's assume it's KOH. Now, As we are doing a reaction with base, means that this reaction can only take places under conditions of SN2 and E2, a fast reaction that is taking place in only 1 step.

With this in mind, let's analyze product a. This states that it has two sp hybridized carbon, in other words, a triple bond between two carbons. So the product is with no doubt, an alkyne.

Product b has only one sp hybridized carbon, which means that this carbon should cannot be an alkyne because we need two carbon atoms. The only way to have one atom of C sp hybridized, is with two double bonds, so product b would have to a alkene with two double bonds.

Product c do not have sp hybridized carbon, therefore, it only has two double bonds in two different Carbon atoms, so it's another alkene with two double bonds, but in two different atoms of carbon.

Picture attached show the product a, b and c. Hope this can help

4 0

3 years ago