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2 years ago

Equate these two equations for acceleration and express, for constant mass, FΔt.

1 answer:

6 0

Acceleration is the rate at which velocity changes.

Simply equate the two.

dV / dt = F/m 
F*dt = dV * m 

The impulse you give any object (average force * time elapsed) is equal to its change in momentum (mass * change in velocity).

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calculate the mass of air in a room if the floor dimensions are 10m × 12m and height is 400 cm the density of air is 1 .26 kg/M³

Burka [1]

Explanation:

first find the volume of room --->

$v \: = 10 \times 12 \times (400 \times {10}^{ - 2} ) \times = 480 \: {m}^{3}$

then find the mass

$mass \: = \: density \: \times \: volume \: = 480 \times 1.26 = 604.8 \: kg$

6 0

2 years ago

Two horizontal pipes have the same diameter, but pipe B is twice as long as pipe A. Water undergoes viscous flow in both pipes,

zheka24 [161]

Answer:

c) 2Q

Explanation:

From the given information:

The pressure inside a pipe can be expressed by using the formula:

$\Delta P = \dfrac{128 \mu L Q}{\pi D^4}$

Since the diameter in both pipes is the same, we can say:

$D = D_A = D_B$

where;

length of the first pipe A $L_A = L$ and the length of the second pipe B $L_B = 2L$

Since the difference in pressure is equivalent in both pipes:

Then:

$\dfrac{128 \mu L_1Q_1}{\pi D_1^4} = \dfrac{128 \mu L_2Q_2}{\pi D_2^4}$

$\dfrac{ L_1Q_1}{D_1^4} = \dfrac{ L_2Q_2}{D_2^4}$

$\dfrac{ LQ_1}{D^4} = \dfrac{ 2LQ}{D^4}$

$\mathbf{Q_1 = 2Q}$

6 0

2 years ago

To make them gas, you have to give liquids yes or no?

jeka94

Answer:

Yes

Explanation:

6 0

2 years ago

Read 2 more answers

A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne

Charra [1.4K]

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

$W_x = 500 cos37$