If the distance of a charged particle from a wire changes from 10cm to 20 cm , what happens to its magnetic field
2 answers:
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Answer: attached
Explanation:
Answer:
The energy of the capacitors connected in parallel is 0.27 J
Given:
C =
C' =
Potential difference, V = 300 V
Solution:
Now, we know that the equivalent capacitance of the two parallel connected capacitors is given by:
The energy of the capacitor, E is given by;