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Naddika [18.5K]
3 years ago
5

If the distance of a charged particle from a wire changes from 10cm to 20 cm , what happens to its magnetic field

Physics
2 answers:
postnew [5]3 years ago
5 0

Answer:

i would say it decreases

Explanation:

bc as distance grows the fields decrease

IM NOT SURE tho

SpyIntel [72]3 years ago
4 0

Answer:

The field is half as strong

Explanation:

The first one is twice as strong

and the last one

The force is reversed

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a white dwarf will become a type ia supernova if group of answer choices the original star was more than 1.38 msun./
Reil [10]

When a white dwarf star is totally annihilated by a nuclear explosion, type Ia supernovae are produced. Type Iax supernovae, a new subtype of supernova, have just been discovered.

<h3>Why do Type 1a supernovae occur?</h3>

It is believed that Type Ia supernovae (SNIa) are produced when a carbon-oxygen white dwarf in a binary system reaches the Chandrasehkar limit, either as a result of accretion from a donor or mergers.

Supernovae of type 1a, in which one of the stars is a white dwarf and there are two stars circling one another, are a kind of supernova that may occur in binary systems. The other star might range in size from a massive star to a tiny white dwarf.

The other star may be anything, even a huge one.

learn more about white dwarf star refer

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3 0
1 year ago
You need to use the diagram to answer 7
Slav-nsk [51]

Your answer is 3 or C

When plates approach one another, the dense plates slips underneath the less dense one

4 0
3 years ago
A 200 g piece of iron is heated to 100°C. It is then dropped into water to bring its temperature down to 22°C. What is the amoun
Amiraneli [1.4K]
The piece of iron is brought from a temperature of 100C to a temperature of 22C. In this process, the heat released by this piece of iron is
Q=m C_s \Delta T
where m=200 g is the mass of the piece of iron, C_s = 0.444 J/(g C) is the iron's specific heat, and the temperature variation is \Delta T = 22^{\circ}-100^{\circ}=-78^{\circ}C. Using these values, the amount of heat released by the iron is
Q=(200 g)(0.441 J/(gC))(-78C)=-6926J=-6.9 kJ
With negative sign because it is amount of heat released. This heat is then trasferred to the water, so the amount of heat absorbed by the water is Q=6.9 kJ.
8 0
3 years ago
Read 2 more answers
A Red Rider bb gun uses the energy in a compressed spring to provide the kinetic energy for propelling a small pellet of mass 0.
Kay [80]

Answer:

a.6.5025 J

b.6.5025 J

Explanation:

We are given that

Mass of pellet,m=0.27 g=0.27\times 10^{-3} kg

1 kg=1000 g

Spring constant,k=1800 N/m

x=8.5 cm=8.5\times 10^{-2} m

1m=100 cm

a.Potential energy stored in the compressed spring  is given by

P.E=\frac{1}{2}kx^2

P.E=\frac{1}{2}(1800)(8.5\times 10^{-2})^2

P.E=6.5025 J

b.By using law of conservation of energy

P.E of spring=K.E of the pellet

K.E of the pellet=6.5025 J

6 0
4 years ago
What is the specific heat (J/g⋅∘C) of a metal object whose temperature increases by 3.0∘C when 17.5 g of metal was heated with 3
lesya692 [45]

Answer:

0.733J/g°C

Explanation:

Using the formula

Q=mcΔθ

Q=38.5J, c=? , m=17.5g , Δθ=3°C

c= Q/(mΔθ)

c=\frac{38.5}{17.5*3}

c=0.733J/g°C

6 0
4 years ago
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