Answer:thermal Energy Transfer in Mixtures Purpose: The purpose of this experiment is to discover how exactly the final temperature of a mixture, involving a substance and hot water, is affected and impacted by the type of substance used. This means that when hot water is mixed with another substance, it must be determined
Explanation:
did this on edge
The correct answer is 1.2 m/s
: mv+mv=mv+mv
(0.5kg)(2m/s)+(0.4kg)(0m/s)=(0.5kg)v+(0.4kg)(1m/s)
= 1kg*m/s=(0.5kg)v+0.4kg*m/s
=1kg*m/s-0.4kg*m/s=(0.5kg)v
=0.6kg*m/s=(0.5kg)v
to solve for v we divide both side by 0.5kg
v=1.2m/s
Answer:
45.89m/s²
Explanation:
Given
Distance S = 305m
Time t = 3.64s
To get the acceleration during this run, we will apply the equation of motion:
S = ut+1/2at²
Substitute the given parameters into the formula and calculate the value of a
305 = 0+1/2 a(3.64)²
304 = 1/2(13.2496)a
304 = 6.6248a
a = 304/6.6248
a = 45.89m/s²
Hence the average acceleration during this run is 45.89m/s²
Answer:
Specific heat of water is 4.186 J/g/C. The heat required to raise the temperature by
is
Here is mass of water being heated, specific heat of water and change in temperature.
Here .
Heat energy required is
Explanation:
