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3 years ago

Which task would be impossible without radio waves ?

Physics

2 answers:

lianna [129]3 years ago

7 0

Yup exactly what the other person said ! ^^i was gonna say the same

nordsb [41]3 years ago

5 0

Answer:

<em>checking your e-mail on your computer using a coffee's shop WiFi. </em>No need radio waves for this.

Explanation:

Because you are only checking it, nothing else.

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A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process? A. velocity and

Lesechka [4]

Answer:

A. velocity and wavelength

Explanation:

When a wave travels from one medium to another it undergoes refraction which results to the change in direction.

Refraction of a wave is one of the property of waves that occurs when a wave changes direction when it passes from one medium to another. This occurs as a result of bending of the wave which occurs since the mediums involved are of different density and refractive index.

Apart from the change in direction, refraction is accompanied by the change in wavelength of a wave and thus a change in speed.

5 0

4 years ago

Two physics students shoot a water-bottle rocket from a 1 m tall stand. They calculate that rocket will travel with the given fo

Kitty [74]

Answer:

2 secs; 65 feet

Explanation:

The function guiding the water bottle is given as:

f(x) = -16t² + 64t + 1

The bottle will reach maximum height when velocity, df/dt (velocity is the first derivative of distance) = 0.

Therefore:

df/dt = 0 = -32t + 64

=> 32t = 64

t = 64/32 = 2 seconds

This is the time it will take to reach the maximum height.

To find this height, we insert t = 2 into the function f(x):

f = -16(2)² + 64(2) + 1

f = -(16 * 4) + 128 + 1

f = -64 + 128 + 1

f = 65 ft

Its maximum height is 65 ft.

7 0

3 years ago

Read 2 more answers

Do you think it is easier or harder to hammer a nail into a floorboard on Pluto than on Earth? How about the Sun? Explain.

Serggg [28]

Explanation:

It would be easier to lift the hammer, during the nailing, in Pluto than on earth but it would require more hammer jacks to drive the nail through the floorboard. This is because the gravity on Pluto is weaker than on Earth. The additional acceleration of the hammer (due to gravity) would be lesser hence you would require to put in a bit more energy for the downforce of the hammer.

On the sun, it would be difficult to lift the hammer than here on earth. This is because the gravity of the sun is much greater than on earth. If you would manage to lift the hammer, the downforce of the hammer on the nail would have an added acceleration of the gravity of the sun hence the force of the hammer hitting the nail would be higher hence rapidly driving it through the floorboard.

Learn More:

For more on gravity check out;

brainly.com/question/9934704

brainly.com/question/3034702

#LearnWithBrainly

7 0

3 years ago

A thin oil slick (no=1.50) floats on water (nw=1.33). When a beam of white light strikes this film at normal incidence from air,

Sedbober [7]

Answer:

The (minimum) thickness of the oil slick is 325 nm.

Explanation:

Let the (minimum) thickness of the oil slick = $t_{o}$

Therefore:

2 $t_{o}$ = ( $m_{red}$ + $\frac{1}{2}$ )*λ $_{red}$ / $n_{o}$ (1)

similarly,

2 $t_{o}$ =( $m_{violet}+\frac{1}{2}$ )*λ $_{violet}$ / $n_{o}$ (2)

Thus, equation 1 = equation 2

( $m_{red}$ + $\frac{1}{2})$ *λ $_{red} /n_{o}$ = ( $m_{violet}+\frac{1}{2})$ *λ $_{violet}/n_{o}$

Where:

λ $_{red} = 650 nm$

λ $_{violet} = 390 nm$

$n_{o} = 1.5$

Therefore:

$\frac{2m_{violet}+1 }{2n_{red}+1 }$ =650/390=5/3

This shows that,

$m_{violet}$ =2

$m_{red}$ =1

Thus, using equation 2

$t_{o}$ = $\frac{5*390}{2*2*1.5} =325 nm$

6 0

3 years ago

Assuming 100% efficient energy conversion, how much water stored behind a 50 centimetre high hydroelectric dam would be required

11Alexandr11 [23.1K]

Complete question is;

Assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery with power rating, 12 V, 50 Ampere-minutes

Answer:

Amount of water required to charge the battery = 7.35 m³

Explanation:

The formula for Potential energy of the water at that height = mgh

Where;

m = mass of the water

g = acceleration due to gravity = 9.8 m/s²

H = height of water = 50 cm = 0.5 m

We know that in density, m = ρV

Where;

ρ = density of water = 1000 kg/m³

V = volume of water

So, potential energy is now given as;

Potential energy = ρVgH = 1000 × V × 9.8 × 0.5 = (4900V) J

Now, formula for energy of the battery is given as;

E = qV

We are given;

q = 50 A.min = 50 × 60 = 3,000 C

V = 12 V

Thus;

qV = 3,000 × 12 = 36,000 J

E = 36,000 J

At a 100% conversion rate, the energy of the water totally powers the battery.

Thus;

(4900V) = (36,000)

4900V = 36,000

V = 36,000/4900

V = 7.35 m³

5 0

3 years ago