1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WARRIOR [948]
2 years ago
14

A 0.50-kg red cart is moving rightward with a speed of 50 cm/s when it collides with a 0.50-kg blue cart that is initially at re

st. After the collision, the blue cart begins moving rightward with a speed of 40 cm/s. The red cart is still moving rightward but has slowed down to a speed of 10 cm/s. Enter the momentum values (in kg•cm/s) of each individual cart and of the system of two carts before and after the collision. Also indicate the change in momentum of each cart.
Physics
1 answer:
9966 [12]2 years ago
5 0

Explanation:

Step one:

given data

mass of red cart m1=0.5kg

initial velocity u1 of red cart=50cm/s

mass of blue cart m2=0.5kg

initial velocity u2 of blue cart= 0cm/s

final velocity v2 of blue cart= 40cm/s

final velocity v1 of red cart= 10cm/s

Step two:

Momentum values red cart before and after the collision.

Before collision

P1=m1u1

P1=0.5*50

P1=25kg•cm/s

After collision

P2=m1v1

P2=0.5*10

P2=5kg•cm/s

Change in momentum= P1-P2=25-5= 20kg•cm/s

Momentum values blue cart before and after the collision.

Before collision

P1=m1u1

P1=0.5*0

P1=0 kg•cm/s

After collision

P2=m1v1

P2=0.5*40

P2=20kg•cm/s

Change in momentum= P1-P2=0-20= -20kg•cm/s

You might be interested in
I need the answer ASAP. Please explain your answer too. 20 points!
Oksana_A [137]

Answer; g

Explanation: the human is a lot smaller than the train

7 0
2 years ago
Consider an opaque horizontal plate that is well insulated on its back side. The irradiation on the plate is 2500 W/m2, of which
GuDViN [60]

Answer:

i. 0.34

ii. 0.4

iii. 1700 w/m²

iv. 2211.36 w/m²

Explanation:

Given that

Irradiation of the plate, G = 2500 w/m²

Reflected rays, p = 500 w/m²

Emissive power, E = 1200 w/m²

See attachment for calculations

8 0
3 years ago
A rocket engine has a chamber pressure 4 MPa and a chamber temperature of 2000 K. Assuming isentropic expansion through the nozz
gladu [14]

This question is incomplete, the complete question is;

A rocket engine has a chamber pressure 4 MPa and a chamber temperature of 2000 K. Assuming isentropic expansion through the nozzle, and an exit Mach number of 3.2, what are the stagnation pressure and temperature in the exit plane of the nozzle?  Assume the specific heat ratio is 1.2.

Answer:

- stagnation pressure is 274.993 Mpa

- the stagnation temperature Tt is 4048 K

Explanation:

Given the data in the question;

To determine the stagnation pressure and temperature in the exit plane of the nozzle;

we us the expression;

Pt/P = (1 + (γ-1 / 2) M²)^(γ/γ -1) = ( Tt/T )^(γ/γ -1)

where Pt is stagnant pressure = ?

P is static pressure = 4 MPa = 4 × 10⁶ Pa  

Tt is stagnation temperature = ?

T is the static temperature  = 2000 K

γ is ratio of specific heats = 1.2

M is Mach number M = 3.2

we substitute

Pt/P = (1 + (γ-1 / 2) M²)^(γ/γ -1)

Pt = P(1 + (γ-1 / 2) M²)^(γ/γ -1)

Pt = 4 × 10⁶(1 + (1.2-1 / 2) 3.2²)^(1.2/1.2 -1)

Pt = 4 × 10⁶ × 68.7484

Pt = 274.993 × 10⁶ Pa

Pt = 274.993 Mpa

Therefore stagnation pressure is 274.993 Mpa

Now, to get our stagnation Temperature

Pt/P = ( Tt/T )^(γ/γ -1)

we substitute

274.993 × 10⁶ Pa / 4 × 10⁶ Pa =  ( Tt / 2000 )^(1.2/1.2 -1)

68.7484 =  Tt⁶ / 6.4 × 10¹⁹

Tt⁶ = 68.7484 × 6.4 × 10¹⁹

Tt⁶ = 4.3998976 × 10²¹

Tt = ⁶√(4.3998976 × 10²¹)

Tt = 4047.999 ≈ 4048 K

Therefore, the stagnation temperature Tt is 4048 K

6 0
3 years ago
a 100 kg gymnast comes to a stop after tumbling. her feet do -5000J of net work to stop her. Use the work-kinetic energy theorem
VikaD [51]
W=ΔKE , W=-5000j
KEinitial=(1/2)mv² , KEfinal=0j 
ΔKE=-(1/2)mv²
-5000=-(1/2)(100kg)v²
v=10 m/s

6 0
3 years ago
Read 2 more answers
17. (16 pts) You set up a two-slit experiment with a laser that produces light with a
Natali [406]

when the two waves interfere with eachother to make a dark spot the periodic difference of the two waves is π . the wave length for 2π is 600nm

. ie. for π difference it is 300nm

4 0
3 years ago
Other questions:
  • What conditions must be present for a translational and rotational equilibrium of a rigid body?
    15·1 answer
  • Which of the following objects would experience the largest force of gravity?
    5·2 answers
  • Which of the following is a major reason for increased female participation in collegiate athletics?1. Title IX legislation2. mo
    6·1 answer
  • 1) Which one of the following is vector,<br>B) Momentum<br>C) Mass<br>A) Energy<br>D) Temperature​
    12·1 answer
  • Which unit represents a value that is one order of magnitude larger than a decimeter?
    5·2 answers
  • Difference between metals and nonmetals​
    10·1 answer
  • What is unit of pressure?why is it called a derived unit ? give reasons​
    10·1 answer
  • Which method is responsible for the transfer of heat in the atmosphere ?
    6·1 answer
  • Which season is signaled by average lower temperature and indirect, angled sunlight?
    12·1 answer
  • Write the energy conversion when a moving car braking to stop completely​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!