Answer:
120 white individuals
30 yellow individuals
10 green individuals
Explanation:
Available data:
- Dominant epistasis: Phenotypic frequencies 12:3:1
- W allele codes for a dominant white phenotype
- w allele codes for a colored squash
- Y allele codes for a dominant yellow phenotype
- y allele codes for a recessive green phenotype
- W allele will always mask the phenotype produced by Y or y alleles
Dihybrid Cross
Parental) WwYy x WwYy
Gametes) WY Wy wY wy
WY Wy wY wy
Punnet Square)
WY Wy wY wy
WY WWYY WWYy WwYY WwYy
Wy WWYy WWyy WwYy Wwyy
wY WwYY WwYy wwYY wwYy
wy WwYy Wwyy wwYy wwyy
F1 Phenotypic Frequency)
White phenotype: 12/16 = 120 individuals
Yellow phenotype: 3/16 = 30 individuals
Green Phenotype: 1/16 = 10 individuals
To know how many offspring are expected to have the white, yellow, and green phenotypes, you can perform a three simple rule. This is:
16 ------- 160 offspring
12 White ------- X = 120 offspring
3 Yellow ------- X= 30 offspring
1 Green --------X = 10 offspring
Would the answer be Translocation for this one?
Explanation:
Morning all C O M E FAST ☺️✌ NAD-UQWR-KGX
