Answer:
option b
Step-by-step explanation:
We have an equation of circle
![(x-7)^2+(y-8)^2=121](https://tex.z-dn.net/?f=%28x-7%29%5E2%2B%28y-8%29%5E2%3D121)
We have to find the center of given circle and radius
We know that general equation of circle with circle (a,b) and radius r
![(x-a)^2+(y-b)^2=r^2](https://tex.z-dn.net/?f=%28x-a%29%5E2%2B%28y-b%29%5E2%3Dr%5E2)
![(x-7)^2+(y-8)^2=(11)^2](https://tex.z-dn.net/?f=%28x-7%29%5E2%2B%28y-8%29%5E2%3D%2811%29%5E2)
By comparing given equation with the general equation of circle
We get centre at x=7 and y=8
Radius =11
Hence, the circle is centered at (7,8) and has a radius of 11.
Option b is true