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mr Goodwill [35]
2 years ago
9

Ehren is trying to increase his mile run from eight to six minutes. He has decided to run some sandy hills near his home. Which

principle of overload is at work? progression time frequency intensity
Physics
1 answer:
densk [106]2 years ago
3 0

Answer:

The correct answer is intensity.

Explanation:

The principle of overload is a basic sports fitness training concept which means that in order to improve, athletes must continually work harder as they their bodies adjust to existing workouts. Thus, overloading also plays a role in skill learning.

Now, since erhen wants to increase his mile run from eight to six minutes by run some sandy hills near his home, it means the principle at work is making his training runs more intense for better speed results. Thus the principle at work is intensity because he is trying to do something that makes him run faster.

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Trình bày về Thí nghiệm tán xạ Rutherford, phát hiện proton.
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Answer:

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3 years ago
Give you point but please i need help in physcis
Anastasy [175]

Explanation:

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7 0
3 years ago
If you add 1 proton to Carbon, it will no longer be Carbon, it will be ________________.
Whitepunk [10]

Nitrogen

Explanation:

Adding one proton to a carbon atom makes Nitrogen.

A quick introspection on atoms:

  • An atom is made up of three fundamental particles.
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  • The protons are positively charged and the neutrons do not carry any charges.
  • Electrons are negatively charged.

The difference between an atom and another is the number of protons in them. This is the atomic number.

The periodic table of element is a list of elements arranged based on the number of protons they have. Every element on the table has unique number of protons which makes it differ from another.

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When an element gains a proton, it becomes another element.

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This is the proton or atomic number of nitrogen.

Learn more:

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4 0
3 years ago
A racecar on a straight track, starting from rest*, steps on the
kirill115 [55]
I think the answer is C
6 0
3 years ago
If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In oth
fgiga [73]

<u>Answer:</u> The elevation in boiling point is 1.024°C.

<u>Explanation:</u>

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=ik_b\times m

where,

i = Van't Hoff factor = 2 (for NaCl)

\Delta T_b = change in boiling point  = ?

k_b = boiling point constant = 0.512^oC/m

m = molality = 1.0 m

Putting values in above equation, we get:

\Delta Tb=2\times 0.512^oC/m\times 1.0m\\\\\Delta Tb=1.024^oC

Hence, the elevation in boiling point is 1.024°C.

5 0
3 years ago
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